The total number of digits used when the first 2002 positive even integers are written is 4 digits
<h3>How to find the number of sequence?</h3>
Using arithmetic sequence,
nth term = a + (n - 1)d
where
- a = first term
- d = common difference
- n = number of terms
a = 2
d = 2
nth term = 2 + (2002 - 1)2
nth term = 2 + 4002
nth term = 4004
learn more on sequence here: brainly.com/question/15456604
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Answer:
look at the picture i sent please
Answer: Option B
Step-by-step explanation: Doing the test, saw another post with the answer
Answer:
D: Sqrt 13
Step-by-step explanation:
I just did it on edg. 2020
Answer:
32
Step-by-step explanation:
