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iren [92.7K]
2 years ago
7

Caculate the density of an object that has a mass of 10 grams

Mathematics
1 answer:
anyanavicka [17]2 years ago
4 0

answer

density= mass/ volume

d =10 g\20cm ^{2}  = 0.5 g \cm^{2}

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50 POINTS FOR THIS 1 QUESTION I JUST NEED THE ANSWER
Oksana_A [137]

Answer:

a = 3

b = 2

c = 0

d = -4

Step-by-step explanation:

Form 4 equations and solve simultaneously

28 = a(2)³ + b(2)² + c(2) + d

28 = 8a + 4b + 2c + d (1)

-5 = -a + b - c + d (2)

220 = 64a + 16b + 4c + d (3)

-20 = -8a + 4b - 2c + d (4)

(1) + (4)

28 = 8a + 4b + 2c + d

-20 = -8a + 4b - 2c + d

8 = 8b + 2d

d = 4 - 4b

Equation (2)

c = -a + b + d + 5

c = -a + b + 4 - 4b+ 5

c = -a - 3b + 9

28 = 8a + 4b + 2c + d (1)

28 = 8a + 4b + 2(-a - 3b + 9) + 4 - 4b

28 = 6a - 6b + 22

6a - 6b = 6

a - b = 1

a = b + 1

220 = 64a + 16b + 4c + d (3)

220 = 64(b + 1) + 16b + 4(-b - 1 - 3b + 9) + 4 - 4b

220 = 60b + 100

60b = 120

b = 2

a = 2 + 1

a = 3

c = -3 - 3(2) + 9

c = 0

d = 4 - 4(2)

d = -4

5 0
3 years ago
Read 2 more answers
Please help i don't understand
olchik [2.2K]

Answer:

Step-by-step explanation:

the answer is 3/7 ‍

5 0
3 years ago
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Given the g(x)=f(x) + k, identify a value of k that transforms f into g
Yuliya22 [10]

Answer:

a vertical shift of 6 units up

Step-by-step explanation:

We have the transformation:

g(x) = f(x) + k

This is what we call a vertical shift, this transformation moves the graph of f(x) k units, and the motion is upwards if k is positive, and downwards if k is negative.

Here we can see that the graph of f(x) intersects the y-axis at y = -2

While the graph of g(x) intersects the y-axis at y = 4.

Then the distance between these two points is:

4 - (-2) = 6

This means that the graph of g(x) is 6 units above the graph of f(x)

Then we have that k must be equal to 6, then the transformation is:

g(x) = f(x) + 6

This is a vertical shift of 6 units up.

8 0
3 years ago
A shopkeeper sold an article at 20 % discount and made a loss of Rs 90. If he had
melamori03 [73]

Answer:

The cost price of the article is Rs 1050

The marked price of the article Rs 1200

Step-by-step explanation:

The given discount on the article = 20%

The amount loss  = Rs 90

With a discount of 5% the amount gained = Rs 90

Let the cost price of the article = X

Let the marked price of the article = Y

Therefore, we have;

(1 - 0.2) × Y = X - Rs 90

(1 - 0.5) × Y = X + Rs 90

Which gives;

0.8·Y = X - Rs 90 .......................(1)

0.95·Y = X + Rs 90.....................(2)

Subtracting equation (1) from equation (2), we have;

0.95·Y-0.8·Y = X + Rs 90 - (X - Rs 90) = X - X + Rs 90 + Rs 90 = Rs 180

0.15·Y = Rs 180

Y = Rs 180/0.15 = Rs 1200

Therefor, the marked price of the article = Rs 1200

From;

0.8·Y = X - Rs 90, we have;

0.8×Rs 1200 = X - Rs 90

X = 0.8× 1200 + 90 = Rs 1050

Therefore, the cost price of the article = Rs 1050.

6 0
3 years ago
Anybody know how to do this ? I need help
Ghella [55]

Answer:

learn more d ko rin kc alam yan heheh

6 0
3 years ago
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