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Zinaida [17]
2 years ago
6

Factoring by grouping x^2 + 4y + 2x + 2xy pls explain with work too!!!

Mathematics
2 answers:
Gennadij [26K]2 years ago
7 0

{x}^{2}  + 4y + 2x + 2xy

We can factorise this expression by grouping. First let us arrange it in this way

=  {x}^{2}  + 2xy + 2x + 4y

Let us bracket them like this:

= ( {x}^{2}  + 2xy) + (2x+ 4y)

In the first bracket portion, take x as common and in the second expression, take 2 as common.

= x(x + 2y) + 2(x + 2y) \\  = (x + 2)(x + 2y)

<u>Answer</u><u>:</u>

(x + 2)(x + 2y)

Hope you could understand.

If you have any query, feel free to ask.

Mamont248 [21]2 years ago
4 0

\tt \:  {x}^{2}  + 4y + 2x + 2xy

Factor out x from the expression

\tt \: x \times (x + 2) + 4y + 2xy

Factor out 2y from the expression

\tt \: x \times (x + 2) + 2y \times (2 + x)

Factor out x+2 from the expression

\boxed{ \sf \: (x + 2) \times (x + 2y)}

➪ <em>Therefore, The factors are: </em>(x+2) & (x+2y)

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