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Zinaida [17]
3 years ago
6

Factoring by grouping x^2 + 4y + 2x + 2xy pls explain with work too!!!

Mathematics
2 answers:
Gennadij [26K]3 years ago
7 0

{x}^{2}  + 4y + 2x + 2xy

We can factorise this expression by grouping. First let us arrange it in this way

=  {x}^{2}  + 2xy + 2x + 4y

Let us bracket them like this:

= ( {x}^{2}  + 2xy) + (2x+ 4y)

In the first bracket portion, take x as common and in the second expression, take 2 as common.

= x(x + 2y) + 2(x + 2y) \\  = (x + 2)(x + 2y)

<u>Answer</u><u>:</u>

(x + 2)(x + 2y)

Hope you could understand.

If you have any query, feel free to ask.

Mamont248 [21]3 years ago
4 0

\tt \:  {x}^{2}  + 4y + 2x + 2xy

Factor out x from the expression

\tt \: x \times (x + 2) + 4y + 2xy

Factor out 2y from the expression

\tt \: x \times (x + 2) + 2y \times (2 + x)

Factor out x+2 from the expression

\boxed{ \sf \: (x + 2) \times (x + 2y)}

➪ <em>Therefore, The factors are: </em>(x+2) & (x+2y)

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Amount of Interest (I) = P * R * T /100
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In short, Your Answer would be $1983.20

Hope this helps!
4 0
3 years ago
The box plot below represents some data set. What is the value of the median?
OLEGan [10]

Answer:

80

Step-by-step explanation:

Look at the box plot and look at each line.

The first line that is all the way to the left, that is the Quartile 1.

The last line all the way to the right, that is Quartile 3.

Now lets look at the box part.

The beggining of the box is the minimum.

The ending of the box is the maximum.

The middle line is the median.

How I remember it is Median=Middle

Hopw this hels :D

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2 years ago
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GalinKa [24]
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3 years ago
The water level in a tank can be modeled by the function h(t)=8cos(pi t /7)+11.5, where t is the number of
denis23 [38]

Answer:

NO amount of hour passed between two consecutive times when the water in the tank is at its maximum height

Step-by-step explanation:

Given the water tank level modelled by the function h(t)=8cos(pi t /7)+11.5. At maximum height, the velocity of the water tank is zero

Velocity is the change in distance with respect to time.

V = {d(h(t)}/dt = -8π/7sin(πt/7)

At maximum height, -8π/7sin(πt/7) = 0

-Sin(πt/7) = 0

sin(πt/7) = 0

Taking the arcsin of both sides

arcsin(sin(πt/7)) = arcsin0

πt/7 = 0

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This shows that NO hour passed between two consecutive times when the water in the tank is at its maximum height

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3 years ago
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\sqrt[2 ]{x} |

\sqrt[?]{?}
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