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GREYUIT [131]
2 years ago
12

Solve. 44 = 5x –11 A. –11 B. –10 C. 10 D. 11

Mathematics
2 answers:
Maslowich2 years ago
7 0

Answer: the answer is D which is x = 11

Step-by-step explanation: swap sides so that all variable terms are on the left-hand side. Add 11 to both sides then add 44 and 11 to get 55. after that divide both sides by 5 then 55 divided by 5 to get to 11.

babunello [35]2 years ago
5 0
The answer is D bebebebdifivjgjdoc
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Given that 5 x − 3 y = 32 Find y when x = 4
ollegr [7]

Answer:

<h2><em>y</em><em>=</em><em>-</em><em>4</em></h2>

<em>Sol</em><em>ution</em><em>,</em>

<em>X=</em><em>4</em>

<em>Now</em><em>,</em>

<em>5x - 3y = 32 \\ or \: 5 \times x - 3y = 32 \\ or \: 5 \times 4 - 3y = 32 \\ or \: 20 - 3y = 32 \\ or \:  - 3y = 32 - 20 \\ or \:  - 3y = 12 \\ or \: y = -   \frac{12}{ 3}  \\ y =  - 4</em>

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4 0
4 years ago
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How do you solve these equations? I don't want you to answer all of them, just tell me how to solve each type of equation on the
miss Akunina [59]

Answer:

8. Identify the common denominator; express each fraction using that denominator; combine the numerators of those rewritten fractions and express the result over the common denominator. Factor out any common factors from numerator and denominator in your result. (It's exactly the same set of instructions that apply for completely numerical fractions.)

9. As with numerical fractions, multiply the numerator by the inverse of the denominator; cancel common factors from numerator and denominator.

10. The method often recommended is to multiply the equation by a common denominator to eliminate the fractions. Then solve in the usual way. Check all answers. If one of the answers makes your multiplier (common denominator) be zero, it is extraneous. (10a cannot have extraneous solutions; 10b might)

Step-by-step explanation:

For a couple of these, it is helpful to remember that (a-b) = -(b-a).

<h3>8d.</h3>

\dfrac{5}{x+2}+\dfrac{25-x}{x^2-3x-10}=\dfrac{5(x-5)}{(x+2)(x-5)}+\dfrac{25-x}{(x+2)(x-5)}\\\\=\dfrac{5x-25+25-x}{(x+2)(x-5)}=\dfrac{4x}{x^2-3x-10}

___

<h3>9b.</h3>

\displaystyle\frac{\left(\frac{x}{x-2}\right)}{\left(\frac{2x}{2-x}\right)}=\frac{x}{x-2}\cdot\frac{-(x-2)}{2x}=\frac{-x(x-2)}{2x(x-2)}=-\frac{1}{2}

___

<h3>10b.</h3>

\dfrac{3}{x-1}+\dfrac{6}{x^2-3x+2}=2\\\\\dfrac{3(x-2)}{(x-1)(x-2)}+\dfrac{6}{(x-1)(x-2)}=\dfrac{2(x-1)(x-2)}{(x-1)(x-2)}\\\\3x-6+6=2(x^2-3x+2) \qquad\text{multiply by the denominator}\\\\2x^2-9x+4=0 \qquad\text{subtract 3x}\\\\(2x-1)(x-4)=0 \qquad\text{factor; x=1/2, x=4}

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8 0
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Answer:

Total rental cost is:

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Let amount of flat fee = M

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                                      ⇒    y = Bx + M

where x is number of additional hours, y is total cost, M is fixed fee, and B are  is amount that is charged per hour.

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Aleks04 [339]

Answer:

infinitely many solutions

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The second equation can be rewritten as 4y = 6x - 4, so the two equations are actually identical.  They have infinitely many solutions.

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