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4 years ago

What value of x makes the equation true?

Mathematics

1 answer:

serious [3.7K]4 years ago

3 0

-4.9=-5.7+0.8
-4.9=-4.9
Answer is C

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Use 2,3,4,5,8 to equal 104

sesenic [268]

To solve this problem do this: ( 3 x 5 x 8 ) - ( 2 x 8 ) = 104

4 0

3 years ago

Read 2 more answers

For the following expression, complete each task:

Scorpion4ik [409]

Part 1: 6x+ -10y+ -2z+ 12
Part 2: What order do you want it to be?
6x+12+-10y+-2z
-2z+-10y+6x+12

Part 3:
2(3x+-5y+-z+6)

8 0

3 years ago

Use the appropriate substitutions to write down the first four nonzero terms of the Maclaurin series for the binomial (1+3x)^(-1

PolarNik [594]

Answer:

First term=1

Second term=-x

Third term= $2x^2$

Fourth term = $-\frac{28}{3!}x^3$

Step-by-step explanation:

We are given that function

$f(x)=(1+3x)^{-1/3}$

We have to find the first four non zero terms of the Maclaurin series for the binomial.

Maclaurin series of function f(x) is given by

$f(x)=f(0)+f'(0)x+\frac{1}{2!}f''(0)x^2+\frac{1}{3!}f'''(0)x^3+....$

$f(0)=(1+3x)^{\frac{-1}{3}}=1$

$f'(x)=-\frac{1}{3}(1+3x)^{-\frac{4}{3}}(3)=-(1+3x)^{-\frac{4}{3}}$

$f'(0)=-1$

$f''(x)=\frac{4}{3}\times 3 (1+3x)^{-\frac{7}{3}}$

$f''(0)=4$

$f'''(x)=-4\times \frac{7}{3}\times 3(1+3x)^{-\frac{10}{3}}$

$f'''(0)=-28$

Substitute the values we get

$(1+3x)^{-\frac{1}{3}}=1-x+\frac{4}{2!}x^2+\frac{-28}{3!}x^3+...$

$(1+3x)^{-\frac{1}{3}}=1-x+2x^2+\frac{-28}{3!}x^3+...$

First term=1

Second term=-x

Third term= $2x^2$

Fourth term = $-\frac{28}{3!}x^3$

5 0

3 years ago

The point-slope form of the equation of the line that passes through (1,-1) and has a slope of 4

Ainat [17]

Answer:y = 4x - 5

Step-by-step explanation:

point slope form is in the form of y = mx + b. m is the slope so we plug thatin and have the equation y = 4x + b. since we also have a point on the line we can plug those into the equation too. -1 = 4 * 1 + b.

now we simplify that through algebra.

-1 = 4 + b

b= -5

sp we get b and we can say the equation is y = 4x -5

7 0

3 years ago

PLEASE HELP 8 ml of a 80% acid solution was mixed with 12 ml of a 20% acid solution. What is the percentage of acid in the new s

noname [10]

Answer:

44%

Step-by-step explanation:

So you have 2 bottles. One bottle is 8ml and is 80% acid. the other is 12 ml and is 20% acid.

This means there's 6.4 ml of acid in bottle 1(8*0.8) and 2.4 ml of acid in the other one(12*0.2).

The total amount of liquid is 8+12 = 20

The total amount of acid is 6.4+2.4 = 8.8

Percentage of acid in the new solution is 8.8/20 = 0.44 = 44%

6 0

3 years ago