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Semmy [17]
3 years ago
9

Find the area of the figure below.​

Mathematics
1 answer:
Anna35 [415]3 years ago
4 0

Answer:

I hope it help..........

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Given the force field F, find the work required to move an object on the given oriented curve. F = (y, - x) on the path consisti
timofeeve [1]

Answer:

0

Step-by-step explanation:

We want to compute the curve integral (or line integral)

\bf \int_{C}F

where the force field F is defined by

F(x,y) = (y, -x)

and C is the path consisting of the line segment from (1, 5) to (0, 0) followed by the line segment from (0, 0) to (0, 9).

We can write  

C = \bf C_1+C_2

where  

\bf C_1 =  line segment from (1, 5) to (0, 0)  

\bf C_2 = line segment from (0, 0) to (0, 9)

so,

\bf \int_{C}F=\int_{C_1}F+\int_{C_2}F

Given 2 points P, Q in the plane, we can parameterize the line segment joining P and Q with

<em>r(t) = tQ + (1-t)P for 0 ≤ t ≤ 1 </em>

Hence \bf C_1 can be parameterized as

\bf r_1(t) = (1-t, 5-5t) for 0 ≤ t ≤ 1

and \bf C_2 can be parameterized as

\bf r_2(t) = (0, 9t) for 0 ≤ t ≤ 1

The derivatives are

\bf r_1'(t) = (-1, -5)

\bf r_2'(t) = (0, 9)

and

\bf \int_{C_1}F=\int_{0}^{1}F(r_1(t))\circ r_1'(t)dt=\int_{0}^{1}(5-5t,t-1)\circ (-1,-5)dt=0

\bf \int_{C_2}F=\int_{0}^{1}F(r_2(t))\circ r_2'(t)dt=\int_{0}^{1}(9t,0)\circ (0,-9)dt=0

In consequence,

\bf \int_{C}F=0

6 0
4 years ago
To covert 5 meters to feet, you need to...
Natali5045456 [20]

Hello!

So 1 meter is 3 feet. So if we have 5 meters, we then multiply 5×3 and your answer will be 15 feet.

I hope it helps!

3 0
3 years ago
Read 2 more answers
WILL GIVE EXTRA BRAINLST <br><br> HAVE A NICE DAy
Nikitich [7]

Answer:

Both answer choices are irrational

Step-by-step explanation:

Irrational means the number cannot be over a fraction or repeating so they are both irrational

hopes this helps

3 0
3 years ago
Y=[[x]]<br> evaluate this function at x=3
dedylja [7]

Step-by-step explanation:

Solution

y=[[x]], at x=3,

therefore the function of y = 3

you can merge 3,3

7 0
3 years ago
In a chemistry course, a student scored 99 on one test, 98 on another test, and 88 on each of the other tests. the student’s tes
Alexxandr [17]
The student took 7 tests. 

99+98+88+88+88+88+88 = 637


637/7 = 91
8 0
3 years ago
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