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Nookie1986 [14]
3 years ago
10

Which inverse operation would be used to verify the following equation?

Mathematics
2 answers:
DochEvi [55]3 years ago
7 0
You would bring the division over to to other side. When we switch it to the other side, it turns into a multiplication (the opposite of division). So we go from:

102 / 3 = 34
to
102 = 34 * 3

Which is C for your multiple choice! :)
Andrej [43]3 years ago
3 0

102 / 3 = 34

to

102 = 34 * 3

Which is C for your multiple choice! :)

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In ΔQRS, the measure of ∠S=90°, the measure of ∠R=29°, and SQ = 5.8 feet. Find the length of RS to the nearest tenth of a foot.
taurus [48]

Answer:

10.5 ft

Step-by-step explanation:

In ΔQRS,

  • m∠S=90°
  • m∠R=29°,
  • SQ = 5.8 feet.

See the diagram below.

The triangle is a Right Triangle,

Using trigonometric ratios,

Tan R=\dfrac{|SQ|}{|RS|} \\Tan 29^\circ=\dfrac{5.8}{|RS|}\\$Cross multiply$\\|RS|XTan 29^\circ=5.8\\|RS|=\dfrac{5.8}{Tan 29^\circ}\\$=10.5 ft (to the nearest tenth of a foot)

7 0
3 years ago
Suppose that you are in charge of evaluating teacher performance at a large elementary school. One tool you have for this evalua
Strike441 [17]

Answer:

a) Standard error = 2

b) Range = (76.08, 83.92)

c) P=0.69

d) Smaller

e) Greater

Step-by-step explanation:

a) When we have a sample taken out of the population, the standard error of the mean is calculated as:

\sigma_m=\dfrac{\sigma}{\sqrt{n}}=\dfrac{10}{\sqrt{25}}=\dfrac{10}{5}=2

where n is te sample size (n=25) and σ is the population standard deviation (σ=10).

Then, the standard error of the classroom average score is 2.

b) The calculations for this range are the same that for the confidence interval, with the difference that we know the population mean.

The population standard deviation is know and is σ=10.

The population mean is M=80.

The sample size is N=25.

The standard error of the mean is σM=2.

The z-value for a 95% confidence interval is z=1.96.

The margin of error (MOE) can be calculated as:

MOE=z\cdot \sigma_M=1.96 \cdot 2=3.92

Then, the lower and upper bounds of the confidence interval are:

LL=M-t \cdot s_M = 80-3.92=76.08\\\\UL=M+t \cdot s_M = 80+3.92=83.92

The range that we expect the average classroom test score to fall 95% of the time is (76.08, 83.92).

c) We can calculate this by calculating the z-score of X=79.

z=\dfrac{X-\mu}{\sigma}=\dfrac{79-80}{2}=\dfrac{-1}{2}=-0.5

Then, the probability of getting a average score of 79 or higher is:

P(X>79)=P(z>-0.5)=0.69146

The approximate probability that a classroom will have an average test score of 79 or higher is 0.69.

d) If the sample is smaller, the standard error is bigger (as the square root of the sample size is in the denominator), so the spread of the probability distribution is more. This results then in a smaller probability for any range.

e) If the population standard deviation is smaller, the standard error for the sample (the classroom) become smaller too. This means that the values are more concentrated around the mean (less spread). This results in a higher probability for every range that include the mean.

6 0
3 years ago
What is 9(x + 8) + x(5+4)
lina2011 [118]

Answer:

72+ 18x

Step-by-step explanation:

9x+72+5x+4x

72+ 18x

7 0
3 years ago
Read 2 more answers
What the answer to lesson 5.4
Anastaziya [24]
0.270 repeated. I used long division and a calculator. hoped this helped.


6 0
3 years ago
What is LP ? <br><br> A. 36<br> B. 40<br> C. 44<br> D. 48<br> E. 52
Sonbull [250]

Answer:

The correct answer is option D.  48

Step-by-step explanation:

From the figure we can see that, some right angled triangles.

<u>To find the measure of LP</u>

Consider the right angled  triangle LPT,

LT is the hypotenuse, LP = 50 units  (given)

PT = QT = RT = 14 units

From figure we get,

LP² + PT² = LT²²

LP² = LT² - PT²

 = 50² - 14²

 = 2500 - 196

 = 2304

LP =√2304

 = 48

The correct answer is option D.  48

8 0
3 years ago
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