Part A
What is the 2010 federal income tax for a single person whose taxable income that year was 4000 dollars?
The function is
T(x)=0.1x
so
For x=4,000
substitute
T(x)=0.1*(4,000)
<h2>T(x)=$400</h2>
Part B
What is the 2010 federal income tax for a single person whose taxable income that year was 170000 dollars?
the function is
T(x)=0.28x-6,290.75
For x=170,000
substitute
T(x)=0.28*(170,000)-6,290.75
<h2>T(x)=$41,309.25</h2>
Part C
What is the taxable income for a single person whose 2010 federal income tax was 105000 dollars?
The function is
T(x)=0.28x-6,290.75
For T(x)=105,000
substitute
105,000=0.28x-6,290.75
solve for x
0.28x=105,000+6,290.75
0.28x=111,290.75
<h2>x=$397,466.96</h2><h2 />
Answer:
The answer is H.
Step-by-step explanation:
You have to apply mid point formula :






Answer: A
Step-by-step explanation:
An ordered pair is a solution if when substituted it makes the equation true. If when you substitute, it does not make the equation true then it is not a solution.
y = -5x - 4
Test:
-52 = -5(10) - 4
-52 = -54 FALSE
Answer:
The average is 1550
Step-by-step explanation:
idk how to do this i just looked up an average calculator
If we can find 1 contradiction then answer is no
hmm
less than one in a fraction is when in form a/b, b>a
1/1000 times 1 and 1/2 same as 1/1000 times 3/2=3/2000
that is less than 1
answer is NO