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3 years ago

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Triangle ABC, with coordinates A(2, 3), B(3, 5), C(7, 4), is dilated by a scale factor of 2. What are the coordinates of the dil

ated figure, triangle A′B′C′? A. A′(4, 6), B′(6, 10), C′(7, 4) B. A′(2, 3), B′(3, 5), C′(7, 4) C. A′(4, 6), B′(6, 10), C′(14, 8) D. A′(4, 6), B′(3, 5), C′(14, 8)

1 answer:

VLD [36.1K]3 years ago

5 0

Answer:I think thats a...

Step-by-step explanation:

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Help please is for now

zmey [24]

Answer: 5

Steps:
5x - 2y = 30
5(8) - 2y = 30
40 - 2y = 30
-2y = 30 - 40
-2y = -10
y = -10/-2
y = 5

I would appreciate the brainliest if this answer was correct and the steps were clear and helpful! :)

3 0

2 years ago

Round 2.408 to the nearest hundredth

Verdich [7]

8 in 2.408 is closer to 10, so you round 2.408 to 2.41

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3 years ago

Read 2 more answers

It is fall and time for joseph to harvest his farm. He currently has 120 acres of wheat. With the help of his farm equipment he

salantis [7]

A. Roc= 14a/d (he can harvest 14 acres per day) so to get 120 acres of wheat he would have to harvest wheat for a little over 5 and a half days

4 0

2 years ago

-10(-5c+4c+7)-3c in simplest form

Snowcat [4.5K]

10(-1c+7)-3c
(-10c+70)-3c
-13c+70 is your answer

4 0

1 year ago

Read 2 more answers

Please help me on this problem

Anna71 [15]

Answer:

The pairs of integer having two real solution for $ax^{2} -6x+c = 0$ are

$a = -4, c = 5$
$a = 1, c = 6$
$a = 2, c = 3$
$a = 3, c = 3$

Step-by-step explanation:

Given

$ax^{2} -6x+c = 0$

Now we will solve the equation by putting all the 6 pairs so we get the following

$-3x^{2} -6x-5 = 0$ for $a = -3 , c=-5$

$-4x^{2} -6x+5 = 0$ for $a = -4 , c=5$

$1x^{2} -6x+6 = 0$ for $a = 1 , c=6$

$2x^{2} -6x+3 = 0$ for $a = 2 , c=3$

$3x^{2} -6x+3 = 0$ for $a = 3 , c=3$

$5x^{2} -6x+4 = 0$ for $a = 5 , c=4$

The above all are Quadratic equations inn general form $ax^{2} +bx+c=0$

where we have a,b and c constant values

So for a real Solution we must have

$Disciminant , b^{2} -4\timesa\timesc \geq 0$

for $a = -3 , c=-5$ we have

$Discriminant =-24$ which is less than 0 ∴ not a real solution.

for $a = -4 , c=5$ we have

$Discriminant = 116$ which is greater than 0 ∴ a real solution.

for $a = 1 , c=6$ we have

$Discriminant =12$ which is greater than 0 ∴ a real solution.

for $a = 2 , c=3$ we have

$Discriminant =12$ which is greater than 0 ∴ a real solution.

for $a = 3 , c=3$ we have

$Discriminant =0$ which is equal to 0 ∴ a real solution.

for $a = 5 , c=4$ we have

$Discriminant =-44$ which is less than 0 ∴ not a real solution.

7 0

3 years ago