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3 years ago

Three times the difference between t and y

Mathematics

1 answer:

7nadin3 [17]3 years ago

7 0

3(t-y) = 3t - 3y <===

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12x>9 (2x-3)-15 solve for x and show steps please.

Verdich [7]

12x > 9(2x-3)-15

distribute the 9

12x > 18x-27 -15

combine like terms on the right side

12x > 18x-42

subtract 18x from both sides

-6x > -42

divide both sides by -6

x = -42 / -6 = 7

x >7

4 0

3 years ago

Read 2 more answers

I just want someone to check if i did all these correctly according to the directions

tekilochka [14]

Answer:

Yes

Step-by-step explanation:

For number 3 you answered them all correctly as well as number 4 and 5. Don't hesitate asking questions like these :D

6 0

3 years ago

Convert the Cartesian equation (x 2 + y 2)2 = 4(x 2 - y 2) to a polar equation.

SashulF [63]

ANSWER

${r}^{2} = 4 \cos2\theta$

EXPLANATION

The Cartesian equation is

${( {x}^{2} + {y}^{2} )}^{2} = 4( {x}^{2} - {y}^{2} )$

We substitute

$x = r \cos( \theta)$

$y = r \sin( \theta)$

and

${x}^{2} + {y}^{2} = {r}^{2}$

This implies that

${( {r}^{2} )}^{2} = 4(( { r \cos\theta) }^{2} - {(r \sin\theta) }^{2} )$

Let us evaluate the exponents to get:

${r}^{4} = 4({ {r}^{2} \cos^{2}\theta } - {r}^{2} \sin^{2}\theta)$

Factor the RHS to get:

${r}^{4} = 4{r}^{2} ({ \cos^{2}\theta } - \sin^{2}\theta)$

Divide through by r²

${r}^{2} = 4 ({ \cos^{2}\theta } - \sin^{2}\theta)$

Apply the double angle identity

$\cos^{2}\theta -\sin^{2}\theta= \cos(2 \theta)$

The polar equation then becomes:

${r}^{2} = 4 \cos2\theta$

7 0

3 years ago

Evaluate 2(4-1)^2 A. 60 B. 30 C. 18 D. 36

iogann1982 [59]

Remember the rules of PEMDAS

1. First you want to evaluate the parentheses. (4-1) = 3

2. Square:
3^2 = 9

3. Multiply: 9*2 = 18

Your answer is C

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3 years ago

The curve formed by a quadratic equation is called a _________

alekssr [168]

The curve formed by a quadratic equation is called a PARABOLA

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3 years ago