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Sindrei [870]
3 years ago
15

Three times the difference between t and y

Mathematics
1 answer:
7nadin3 [17]3 years ago
7 0
3(t-y) = 3t - 3y <===
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12x&gt;9 (2x-3)-15 solve for x and show steps please.
Verdich [7]

12x > 9(2x-3)-15

distribute the 9

12x > 18x-27 -15

combine like terms on the right side

12x > 18x-42

subtract 18x from both sides

-6x > -42

divide both sides by -6

x = -42 / -6 = 7

x >7

4 0
3 years ago
Read 2 more answers
I just want someone to check if i did all these correctly according to the directions
tekilochka [14]

Answer:

Yes

Step-by-step explanation:

For number 3 you answered them all correctly as well as number 4 and 5. Don't hesitate asking questions like these :D

6 0
3 years ago
Convert the Cartesian equation (x 2 + y 2)2 = 4(x 2 - y 2) to a polar equation.
SashulF [63]

<u>ANSWER</u>

{r}^{2}  = 4  \cos2\theta

<u>EXPLANATION</u>

The Cartesian equation is

{( {x}^{2}  +  {y}^{2} )}^{2}  = 4( {x}^{2} -  {y}^{2}  )

We substitute

x = r \cos( \theta)

y = r \sin( \theta)

and

{x}^{2}  +  {y}^{2}  =  {r}^{2}

This implies that

{( {r}^{2} )}^{2}  = 4(( { r \cos\theta)  }^{2} -  {(r \sin\theta) }^{2}  )

Let us evaluate the exponents to get:

{r}^{4}  = 4({  {r}^{2} \cos^{2}\theta } -   {r}^{2}  \sin^{2}\theta)

Factor the RHS to get:

{r}^{4}  = 4{r}^{2} ({   \cos^{2}\theta } -   \sin^{2}\theta)

Divide through by r²

{r}^{2}  = 4 ({   \cos^{2}\theta } -   \sin^{2}\theta)

Apply the double angle identity

\cos^{2}\theta -\sin^{2}\theta=  \cos(2 \theta)

The polar equation then becomes:

{r}^{2}  = 4  \cos2\theta

7 0
3 years ago
Evaluate 2(4-1)^2<br><br> A. 60<br> B. 30<br> C. 18<br> D. 36
iogann1982 [59]
Remember the rules of PEMDAS

1. First you want to evaluate the parentheses. (4-1) = 3

2. Square:
3^2 = 9

3. Multiply: 9*2 = 18

Your answer is C
4 0
3 years ago
The curve formed by a quadratic equation is called a _________
alekssr [168]
<span>The curve formed by a quadratic equation is called a PARABOLA</span>
3 0
3 years ago
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