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2 years ago

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What are the factors of 345

1 answer:

Gnesinka [82]2 years ago

6 0

Answer:

1,3,5,345 are factors of 345

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If a person lnvests $120 at 8% annual interest, find the approximate value of the investment at the end of 5 years

Pie

Answer:

$176.3193692 or $176.32 (rounded to two decimal places)

Step-by-step explanation:

It is a compound interest, which means the interest accumulates on an initial amount each period.

The formula is A=P(1+R)^n

A= the total amount P=initial amount R=rate n=time (years)

P=$120 Rate= 8% or 0.08 (decimal) n=5 (years)

A=120 (1+0.08)^2

A=120 (1.469328077)

A= 176.3193692

6 0

1 year ago

Solve for x. Round to the nearest tenth.

Misha Larkins [42]

Answer:

Step-by-step explanation:

Youre given the adjacent and hypotenuse, so you can use cosine. SOHCAHTOA

cos(37) = 48/x

x = 60.1

5 0

2 years ago

Sean b= 5,79; c= 10,4,el angulo A= 54,46°, el angulo C mide ?

Rzqust [24]

Answer:

$C \approx 91.732^{\circ}$

Step-by-step explanation:

(This exercise is presented in Spanish and for that reason explanation will be held in such language)

El lado restante se determina por la Ley del Coseno:

$a = \sqrt{b^{2}+c^{2}-2\cdot b\cdot c \cdot \cos A}$

$a = \sqrt{5.79^{2}+10.4^{2}-2\cdot (5.79)\cdot (10.4)\cdot \cos 54.46^{\circ}}$

$a \approx 8.466$

Finalmente, el angulo C se halla por medio de la misma ley:

$\cos C = - \frac{c^{2}-a^{2}-b^{2}}{2\cdot a \cdot b}$

$\cos C = -\frac{10.4^{2}-8.466^{2}-5.79^{2}}{2\cdot (8.466)\cdot (5.79)}$

$\cos C = -0.030$

$C \approx 91.732^{\circ}$

3 0

2 years ago

Find the absolute maximum and minimum values of the following function on the given interval. If there are multiple points in a

Bond [772]

$f(x)=3\sin x+3\cos x\implies f'(x)=3\cos x-3\sin x$

$f$ has critical points where $f'=0$ :

$3\cos x-3\sin x=0\implies\cos x=\sin x\implies\tan x=1\implies x=\pm\dfrac\pi4+2n\pi$

where $n$ is any integer. We get solutions in the interval $\left[0,\frac\pi3\right]$ for $n=0$ , for which $x=\frac\pi4$ .

At this critical point, we have $f\left(\frac\pi4\right)=3\sqrt2\approx4.243$ .

At the endpoints of the given interval, we have $f(0)=3$ and $f\left(\frac\pi3\right)=\frac{3+3\sqrt3}2\approx4.098$ .

So we have the extreme values

$\max\limits_{x\in\left[0,\frac\pi3\right]}f=3\sqrt2$

$\min\limits_{x\in\left[0,\frac\pi3\right]}f=3$

8 0

3 years ago

Determine the distance between (-5,2) and (-2,5). show your work. round to the nearest tenth if necessary.

statuscvo [17]

Answer

-2

Step-by-step explanation:

learn how to do your work f^gg0+

4 0

2 years ago