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2 years ago

Aaaa i’ve been seeing something close to this but not the same answer

Mathematics

2 answers:

vagabundo [1.1K]2 years ago

8 0

Answer:

what does the picture say?

Step-by-step explanation:

igomit [66]2 years ago

7 0

Answer: 504 I THINK

Love me some ration questions lol!

2:7

114:504

you can work this out by putting the ration in a column eg 2:7

and if you know how many spots are in one column like for the 2 in 2:7 has 114 spots then you need to find oht how many are in that 114! basically just do 114 ÷ 2 =72 then use 72 to multiply the 7 (in 2:7) by 72 which makes 504.

I THINK THIS IS THE ANSWERIM REALLY SORRY IF MY ANSWER TURNS OUT WRONG!!

hops this helps!

Havs a good fridsy xo

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Find the area a polygon jklmno

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Area of polygon = (number of sides × length of one side × apothem)/2

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2 years ago

= a fx The function f is defined by f (x) = 50-3^x. The function g is defined by g(x) = a · Here are graphs of f and g. y مه f Х

Margaret [11]

Answer:

Step-by-step explanation:

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2 years ago

Using Euler’s Method with a step size of h=0.5, estimate the value for y(3) for the differential equation xy dy/dx= 1+ln(x^2), w

lora16 [44]

Euler's method uses the recurrence relation

$y_{n+1}=y_n+hf(x_n,y_n)$

to approximate the value of the solution $y(x)$ to the ODE $y'=f(x,y)$ .

$xy\dfrac{\mathrm dy}{\mathrm dx}=1+\ln(x^2)\implies y'=\dfrac{1+\ln(x^2)}{xy}=f(x,y)$

With a step size of $h=0.5$ , there will only be two steps necessary to find the approximate value of $y(3)$ based on the initial point $y(2)=5$ . See the attached table below for the computation results.

To demonstrate how the table is generated: Since $y(2)=5$ , you are using $(x_0,y_0)=(2,5)$ .

$y_1=y_0+hf(x_0,y_0)$
$y_1=5+0.5\times\dfrac{1+\ln(2^2)}{2\times5}$
$y_1\approx5.1193$

The next point then uses $x_1=x_0+0.5=2.5$

$y_2=y_1+hf(x_1,y_1)$
$y_1=y_1+0.5\times\dfrac{1+\ln(2.5^2)}{2.5y_1}$
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2 years ago

Geometry:(<br><br> will give brainist to correct answer:)

Lorico [155]

Given:

End points a line segment are (9,-8) and (-1,-4).

To find:

The equation of perpendicular bisector of given line.

Solution:

Slope of given line is

$m=\dfrac{y_2-y_1}{x_2-x_1}$

$m_1=\dfrac{-4-(-8)}{-1-9}$

$m_1=\dfrac{-4+8}{-10}$

$m_1=\dfrac{4}{-10}$

$m_1=-\dfrac{2}{5}$

Product of slopes of two perpendicular line is -1.

$m_1\times m_2=-1$

$(-\dfrac{2}{5})\times m_2=-1$

$m_2=\dfrac{5}{2}$

So, slope of perpendicular bisector is $\dfrac{5}{2}$ .

Perpendicular bisector passes through the midpoint of given endpoints.

$Midpoint=\left(\dfrac{x_1+x_2}{2},\dfrac{y_1+y_2}{2}\right)$

$Midpoint=\left(\dfrac{9+(-1)}{2},\dfrac{(-8)+(-4)}{2}\right)$

$Midpoint=\left(\dfrac{8}{2},\dfrac{-12}{2}\right)$

$Midpoint=\left(4,-6\right)$

So, perpendicular bisector passes through (4,-6) and having slope $\dfrac{5}{2}$ . The equation of perpendicular bisector is

$y-y_1=m(x-x_1)$

where, m is slope.

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$y+6=\dfrac{5}{2}(x)+\dfrac{5}{2}(-4)$

$y+6=\dfrac{5}{2}x-10$

$y=\dfrac{5}{2}x-10-6$

$y=\dfrac{5}{2}x-16$

Therefore, the equation of perpendicular bisector is $y=\dfrac{5}{2}x-16$ .

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