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Gemiola [76]
3 years ago
9

At noon, the temperature of a container of ether was –109⁰C. At 1 p.m., the temperature of the container of ether was –34⁰C. Wha

t was the change in temperature from noon to 1 p.m.? 
Mathematics
1 answer:
dem82 [27]3 years ago
5 0
143 degrees celcius because you do 109--34 
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You are buying balloons for a party. A small balloon costs ​$2. A large balloon costs ​$4. Write an algebraic expression for the
miv72 [106K]

Answer:

2x + 4y

$40

Step-by-step explanation:

Equation for x small balloons and y large balloons

2x + 4y

Total cost of 10 small balloons and 5 large balloons

x = 10, y = 5

2(10) + 4(5)

= 20 + 20

= $40

8 0
3 years ago
What time is 5 3/4 hours after 11:32 pm?<br> Please show work, thank you.
poizon [28]

we have to first convert fraction of hours into minutes

1 hour is equivalent to 60 minutes

then 3/4 hour is - 3/4 of 60

when the of function is used we have to multiply the 2 numbers

then \frac{3}{4} * 60 = \frac{3*60}{4} = \frac{180}{4} = 45

3/4 of an hour is equivalent to 45 minutes

then we have to add 5 hours and 45 minutes to 11.32 pm

add 5.45 to 11.32


11.32

5.45 +

-------

16.77

then its 16 hours and 77 minutes

an hour has only 60 minutes so we subtract 60 minutes from 77 minutes and add that hour to 16 hours

16 hours + 1 = 17 hours 

77 minutes - 60 minutes = 17 minutes

17 hours 17 minutes

time is given in pm therefore its a 12 hour clock

so we have to subtract 12 hours from 17 hours 17 minutes

17.17 hours - 12 hours = 5.17

the new time is 5.17 am of the next day



8 0
3 years ago
Read 2 more answers
I need help in this one please
zhenek [66]
I need more information
8 0
3 years ago
Please help with all of question 4.​
olga55 [171]

Answer:

Step-by-step explanation:

Combine like terms: Like terms have same variable with same power and to combine the like terms, add/subtract the co efficient of the variables.

<h3>Perimeter:</h3>

      Perimeter = sum of all sides

a) Perimeter of ΔABC = AB + BC + CA

                                    = x + 14 + x + 14 + x + 14

                                    = x + x + x + 14 + 14 + 14    {Combine like terms}

                                   = 3x + 42

b) EF = DI - GH

        = 2x + 3 - x

       = 2x - x + 3

       = x + 3

c) FG = HI - ED

         = 12 + 2x - (x + 5)

         = 12 + 2x - x - 5 {To open the brackets, (-1) is distributed to x and 5}

         = 12 - 5 + 2x - x

         = 7 + x

d) Perimeter of DEFGHI = DE +  EF + FG + GH + HI + ID

                                       =  x + 5 + x + 3 + 7 +x  + x + 12 +2x + 2x + 3

                                       = x +x + x + x + 2x + 2x + 5 + 3 + 7 + 3 + 12  

                                       = 8x + 30

6 0
2 years ago
Rodrigo's math certificate is 20 centimeters tall and 27 centimeters wide. Rodrigo wants to put the certificate in a fancy frame
Lapatulllka [165]

Answer:

the cost that used to frame the math certificate is $847.80

Step-by-step explanation:

The computation of the cost that used to frame the math certificate is shown below:

= 27 wide × 20 tall × $1.57 per centimeter

= $847.80

Hence, the cost that used to frame the math certificate is $847.80

5 0
2 years ago
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