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3 years ago

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At noon, the temperature of a container of ether was –109⁰C. At 1 p.m., the temperature of the container of ether was –34⁰C. Wha

t was the change in temperature from noon to 1 p.m.?

1 answer:

dem82 [27]3 years ago

5 0

143 degrees celcius because you do 109--34

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1. Kim's age is twice that of her sister. When you add Kim's age to her sister's age, you get 36. How old is each sister? (a) Wr

Jlenok [28]

A)
Kim's age=k
Sister's age=s
k=2s
k+s=36
b)
k=2s
k+s=36
k=36-s
2s=36-s
3s=36
s=12
12*2=24
Kim is 24 and her sister is 12

Hope this helps :)

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3 years ago

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point a has the coordinates(2,5) point B has the coordinates (6,17) how long is segment ab in simplified radical form

IRISSAK [1]

Answer:

$4\sqrt{10}$

Step-by-step explanation:

We have been given that point A has the coordinates(2,5) point B has the coordinates (6,17).

To find the length of segment AB we will use distance formula.

$\text{Distance}=\sqrt{(x_2-x_1)^2+(y_2-y_1)^2}$

Upon substituting coordinates of point A and point B in distance formula we will get,

$\text{Distance between point A and point B}=\sqrt{(6-2)^2+(17-5)^2}$

$\text{Distance between point A and point B}=\sqrt{(4)^2+(12)^2}$

$\text{Distance between point A and point B}=\sqrt{16+144}$

$\text{Distance between point A and point B}=\sqrt{160}$

$\text{Distance between point A and point B}=4\sqrt{10}$

Therefore, the length of segment AB is $4\sqrt{10}$ .

3 0

3 years ago

Help fill in the blanks no

DerKrebs [107]

Answer:

Here is the full proof:

AC bisects ∠BCD Given

∠CAB ≅ ∠CAD Definition of angle bisector

DC ⊥ AD Given

∠ADC = 90° Definition of perpendicular lines

BC ⊥ AB Given

∠ABC = 90° Definition of perpendicular lines

∠ADC ≅ ∠ABC Right angles are congruent

AC = AC Reflexive property

ΔCAB ≅ ΔCAD SAA

BC = DC CPCTC

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3 years ago

Draw a number line that shows the distance between 3 and -2 is 5

NISA [10]

This is how I would do it, hope this helps!

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3 years ago

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The formula for the volume of a cone is V=1/3 pi r2h the radius r of the cone may be expressed as

Naily [24]

r = √(3V/πh)

multiply both sides by 3 to eliminate the fraction

πr²h = 3V ( divide both sides by πh )

r² = 3V/ πh ( take the square root of both sides )

r = √(3V/πh)

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2 years ago

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