Answer:
D
Step-by-step explanation:
Independent and dependent variables are exactly what they sound like.
The amount of money he gets paid <em>depends </em>on how long he babysits.
The ages of the children don't matter at all.
Answer:
0.04,0.25.0.52
Step-by-step explanation:
Given that you throw a dart at a circular target of radius 10 inches.
Assuming that you hit the target and that the coordinates of the outcomes are chosen at random,
probability that the dart falls
(a) within 2 inches of the center
Here favourable region has area of a circle with radius 2 inches and sample space has area of 10 inches
Prob = 
(b) within 2 inches of the rim.
For within two inches from the rim we have to select area of the ring i.e. area of big circle with 10 inches - area of smaller circle with 10-2 inches
Prob= 
c) within I quadrant
area of I quadrant / area of circle=0.25
d) within I quadrant and within 2 inches of the rim
= I quadrant area + 2 inches ring area - common area
= 
You need to add one equation to the other. To do this, multiply the divide the entire equation by 2. The resulting equation gives: -6x + 3y = 9
Now, add this to the second. Doing this will cancel out the 6xs because they are opposite signs.
-4y = 4 is your simplified equation.
Solve for y: y = -1
Plug this into an original equation.
-12x + 6(-1) = 18
-12x -6 = 18
-12x = 24
x = -2
<span>If length = 12, then width = 3
If length = 3, then width = 12</span>