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Fynjy0 [20]
3 years ago
14

The increase in a person’s body temperature T(t), above 98.6ºF, can be modeled by the function mc025-1.jpg, where t represents t

ime elapsed. What is the meaning of the horizontal asymptote for this function? The horizontal asymptote of y = 0 means that the person’s temperature will approach 98.6ºF as time elapses. The horizontal asymptote of y = 0 means that the person’s temperature will approach 0ºF as time elapses. The horizontal asymptote of y = 4 means that the person’s temperature will approach 102.6ºF as time elapses. The horizontal asymptote of y = 4 means that the person’s temperature will approach 4ºF as time elapses.
Mathematics
1 answer:
Anarel [89]3 years ago
4 0
Horizontal asymptote is what happens to T(f) as t becomes extremely large (approaches infinity).  The horizontal asymptote is the line which T(t) approaches as t goes to infinity, i.e. the line y=0. This means that the person's body temperature will approach 0ºF above 98.6ºF as t goes to infinity. i.e. the person's body temperature will approach 98.6ºF as time lapses. The first option.
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2 years ago
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stepan [7]

<u>Answer:</u>

The correct answer option is: S_9=\frac{9}{2} (2+26)

<u>Step-by-step explanation:</u>

We know that,

the sum of the first n terms of an Arithmetic Sequence is given by:

S_9=\frac{n(a_1+a_n)}{2}

where n is the number of terms,

a_1 is the first term of the sequence; and

a_n is the first term of the sequence.

So for a_n=3n-1,

a_1=3(1)-1=2

and

a_9=3(9)-1=26

Putting these values in the formula to get:

S_9=\frac{9(a_1+a_9)}{2}

S_9=\frac{9(2+26)}{2} \\\\S_9=\frac{9}{2} (2+26)

<u>First five terms:</u>

a_1=3(1)-1=2

S_1=\frac{1(2+2)}{2}=2


a_2=3(2)-1=5

S_2=\frac{2(2+5)}{2}=7


a_3=3(3)-1=8

S_2=\frac{3(2+8)}{2}=15


a_4=3(4)-1=11

S_4=\frac{4(2+11)}{2}=26


a_5=3(5)-1=14

S_5=\frac{5(2+14)}{2}=40



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