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Agata [3.3K]
2 years ago
11

What are the lengths of SV and QT? no links.

Mathematics
2 answers:
4vir4ik [10]2 years ago
5 0

Answer:

TR = 12

=> 3x + 2 =17

=> x = 5

We have QT = QV (because QTV is an isosceles triangle)

=> QT = 4x+1=4x5+1=21 units

We have TS = SV (because TSV is an isosceles triangle)

=>SV = 9x-4= 9x5-4=41 units

maxonik [38]2 years ago
4 0

ok so we see that TR is 17 units, so RV is the same amount

3x+2 so 3x=15 so divide both sides by 3 we get x=5

now we know x=5 4x+1=21 and 9x-4=41

*drops microphone*

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Simplify<br> V100 + V36 - V150
motikmotik

Answer:

16  - 5 \sqrt{6}

Step-by-step explanation:

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3 years ago
A man made reservoir is filled in 15 days by 4 piples,if 4 pipes are used ,how long will it take to fill the reservoir
Delicious77 [7]
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3 0
3 years ago
How to solve all of this
photoshop1234 [79]
Start circle: πd = (3.14)(19) = 59.7

Move diagonally to the circle with the radius of 6.2.

Second circle: 2πr = 2(3.14)(6.2) = 39

Move upwards to the circle with the radius of 10.5

third circle: 2πr = 2(3.14)(10.5) = 66

Move right to the circle with the diameter of 16.6

Fourth circle: πd = (3.14)(16.6) = 52.2

Move down to the circle with the diameter of 7.7

fifth circle: πd = (3.14)(7.7) = 24.2

Move down to the circle with the diameter of 50

Sixth circle: πd = (3.14)(50) = 157.1

Move left to the circle with the radius of 11.8

Seventh circle: 2πr = 2(3.14)(11.8) = 74.1

Move down to the circle with the radius of 38

Eight circle: 2πr = 2(3.14)(38) = 238.8

Move right to the circle with the diameter of 1.1

ninth circle: πd = (3.14)(1.1) = 3.5

Move right to the circle with the radius of 14.8

10th circle = 2πr = 2(3.14)(14.8) = 93

Move up to the end.

Hope this helps :) 
7 0
3 years ago
I need help with this maths homework please
valentinak56 [21]
I found this on another question made before

4 0
2 years ago
What would the answer be???
Korolek [52]

Answer:

The solution is obtained by adding the two equations.

The solution is: (x, y) = ($ - \frac{2}{3} $, $ - \frac{7}{3} $)

Step-by-step explanation:

We are given two equations with two variables. The strategy is to eliminate one variable and solve for both the variables.

The two equations are:

$ 7x + y = - 7 \hspace{15mm} \hdots (1) $

$ 2x - y = 1 \hspace{15mm} \hdots (2) $

Adding both the equations, we get:

$ 7x + 2x + y - y = - 7 + 1 $

$ \implies 9x = - 6 $

$ \implies x = - \frac{2}{3} $

Substituting the value of 'x', we get the value of y.

We substitute in (2). [Can be substituted in any equation].

We get: y = 2x - 1

$ \imples y = 2\bigg(\frac{-2}{3}\bigg) - 1 $

$ \implies -\frac{4}{3} - 1 $

$ \implies y = -\frac{7}{3} $

So, we get the corresponding values of x and y which is the solution of the two equations.

4 0
3 years ago
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