If tan theta is -1, we know immediately that theta is in either Quadrant II or Q IV. We need to focus on Q IV due to the restrictions on theta.
Because tan theta is -1, the ray representing theta makes a 45 degree angle with the horiz axis, and a 45 degree angle with the negative vert. axis. Thus the hypotenuse, by the Pythagorean Theorem, tells us that the hyp is sqrt(2).
Thus, the cosine of theta is adj / hyp, or +1 / sqrt(2), or [sqrt(2)]/2
The secant of theta is the reciprocal of that, and thus is
2 sqrt(2)
---------- * ------------ = sqrt(2) (answer)
sqrt(2) sqrt(2)
Think about this as a table of values where domain is the x values and range is the y values.
f(4) wants the y-value when the x-value is 4
f(4) = 1/2
The second question wants us to find the x-value when f(x) also known as the y-value is 4.
f(x) = 4
x = 8
answers: 1/2, 8
Make 2 equations let x=150 y=600/180000 than plug and chug
Answer: B. 2x + 2 + x
Step-by-step explanation:
I took the quiz.
Answer:
p(-10) = 31
Step-by-step explanation:
Plug in -10 as x into the equation, and solve
p(x) = x + 41
p(-10) = -10 + 41
p(-10) = 31