Answer:
2 (real) solutions.
Step-by-step explanation:
A quadratic always has two solutions, whether they are real or complex.
Sometimes the solution is complex, involving complex numbers (2 complex), sometimes they are real and distinct (2 real), and sometimes they are real and coincident (still two real, but they are the same).
In the case of
x^2+3x = 3, or
x² + 3x -3 = 0
we apply the quadratic formula to get
x = (-3 +/- sqrt(3^2+4(1)(3))/2
to give the two solutions
{(sqrt(21)-3)/2, -(sqrt(21)+3)/2,}
both of which are real.
Hey, there’s no circle for me to look at unfortunately!
Answer:
The answer of this question is (D) 8
Answer:
23 Cm(2)
Step-by-step explanation:
Sincerest Apologies if it is incorrect
if it's not 23 it may be:
26 Cm(2)
The mode's of this set of data are 1,2, and 4.
