Answer:
d. 9 integers
Step-by-step explanation:
Given that two numbers are said to be 'relatively prime' if their greatest common factor is 1.
We are to find relatively prime with 28 which are greater than 10 and less than 30
We have 11,12,13...29 satisfying the criteria greater than 10 and less than 30
To be relatively prime with 28, common factors should be only 1.
28 = 2x2x 7. Hence the numbers which do not have factors as 2 or 7 will be relatively prime. Remove all the even numbers from the list.
We have 11,13,15....29.
Of these 21 is the multiple of 7 so remove that.
Thus we have now 11,13,15,17,19,23,25,27,29
9 integers
d. 9 integers
9We have such eqation
Q

/*9 (multiply both sides by 9)
9Q+5=

/-5 both sides
9Q=

9Q=

9Q=

9Q=-

/:9 divide both sides by 9
Q=-

Q
![\frac{21}{6*9} =- \frac{21}{54}=[tex] \frac{7}{18}](https://tex.z-dn.net/?f=%20%5Cfrac%7B21%7D%7B6%2A9%7D%20%3D-%20%5Cfrac%7B21%7D%7B54%7D%3D%5Btex%5D%20%5Cfrac%7B7%7D%7B18%7D%20)
- its the answer
Answer:
First one is 41
Second one is 87
Step-by-step explanation:
Make the shaded part as a trapezoid which is (3+6)*10/2 you just have to get rid of 2*2. So you get 41 as the answer.
The unshaded part will be 16*8 then subtracts the shaded part which is 41. Then you get the answer 87.
Answer:
I think it is 8
Step-by-step explanation:
I did the math on paper