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1 year ago

Plz I need help can you solve this

Mathematics

1 answer:

tester [92]1 year ago

6 0

Hey there,

Please check the picture attached as my answer.

Convey me if you have any doubts.

~ Benjemin360

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If 9 oranges cost £1.62 how much is 1 orange

Taya2010 [7]

.18
.90
but i don't recognize that currency
hope this helps

7 0

2 years ago

Sharon is planning a holiday for 4 people for 7 days.

Eduardwww [97]

1 person = 130 + (60x7) + 350 = 900
4 people = 4 x 900 = 3600
I think this is right !

6 0

2 years ago

Read 2 more answers

1.) Jasmine earns her regular pay of $9.50 per hour for up to 40 hours of

HACTEHA [7]

Answer:

$408.25

Step-by-step explanation:

9.50 times 40=380

9.50 times 1.5= 14.25

14.25 times 2=28.50

380+28.50=

$408.25

4 0

2 years ago

Read 2 more answers

A researcher compares the effectiveness of two different instructional methods for teaching electronics. A sample of 138 student

yan [13]

Answer:

The 98% confidence interval for the true difference between testing averages for students using Method 1 and students using Method 2 is (-8.04, 0.84).

Step-by-step explanation:

The (1 - <em>α</em>)% confidence interval for the difference between population means is:

$CI=(\bar x_{1}-\bar x_{2})\pm z_{\alpha/2}\times \sqrt{\frac{\sigma^{2}_{1}}{n_{1}}+\frac{\sigma^{2}_{2}}{n_{2}}}$

The information provided is as follows:

$n_{1}= 138\\n_{2}=156\\\bar x_{1}=61\\\bar x_{2}=64.6\\\sigma_{1}=18.53\\\sigma_{2}=13.43$

The critical value of <em>z</em> for 98% confidence level is,

$z_{\alpha/2}=z_{0.02/2}=2.326$

Compute the 98% confidence interval for the true difference between testing averages for students using Method 1 and students using Method 2 as follows:

$CI=(\bar x_{1}-\bar x_{2})\pm z_{\alpha/2}\times \sqrt{\frac{\sigma^{2}_{1}}{n_{1}}+\frac{\sigma^{2}_{2}}{n_{2}}}$

$=(61-64.6)\pm 2.326\times\sqrt{\frac{(18.53)^{2}}{138}+\frac{(13.43)^{2}}{156}}\\\\=-3.6\pm 4.4404\\\\=(-8.0404, 0.8404)\\\\\approx (-8.04, 0.84)$

Thus, the 98% confidence interval for the true difference between testing averages for students using Method 1 and students using Method 2 is (-8.04, 0.84).

5 0

2 years ago

This is for the last post

Mazyrski [523]

Answer:

Well for Part A-

List the temperatures from least to greatest; anything under 0 degrees is the lowest.

-6.1

-2.5

-0.4

3.4

And for Part B-

You can use a number line to order the temperatures because it's a good way to sort which ones are the lowest and highest easily.

5 0

2 years ago