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2 years ago

11

Plz I need help can you solve this

1 answer:

tester [92]2 years ago

6 0

Hey there,

Please check the picture attached as my answer.

Convey me if you have any doubts.

~ Benjemin360

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Shelley drove a car for 476 miles using 17 gallons of gas. At that rate, how many miles can she travel by car using 30 gallons o

lana [24]

At this rate she can travel 840 miles using 30 gallons of gas.

7 0

3 years ago

Which sentence can represent the inequality 2.4 (6.2 minus x) greater-than negative 4.5? Two and four tenths times six and two t

jeka57 [31]

Answer:

I think C

Step-by-step explanation:

4 0

3 years ago

Read 2 more answers

Given the Trapezoid ABCD<br><br> Find the length of AD <br><br> Pls hellpppp

matrenka [14]

Given:

In trapezoid $ABCD, AD\parallel BC, MN$ is the mid-segment of $ABCD, AD=30x-10,MN=31x+1,BC=30x+28$ .

To find:

The length of $AD$ .

Solution:

We know that the length of the mid-segment of a trapezoids is half of the sum of lengths of two parallel sides of the trapezoid.

In trapezoid $ABCD$ ,

$MN=\dfrac{AD+BC}{2}$

$31x+1=\dfrac{30x-10+30x+28}{2}$

$31x+1=\dfrac{60x+18}{2}$

$31x+1=30x+9$

Isolate variable terms.

$31x-30x=9-1$

$x=8$

Now,

$AD=30x-10$

$AD=30(8)-10$

$AD=240-10$

$AD=230$

Therefore, the length of $AD$ is 230.

6 0

2 years ago

Can anyone help for brainst and a thanks?

bekas [8.4K]

Answer:

$150.

Step-by-step explanation:

You would add to get the answer.

57 + 90 = 150.

Feel free to let me know if you need more help. :)

8 0

3 years ago

What is the answer to (6+4)tothe3power-1tothe8power

Ipatiy [6.2K]

Hey there!

$\huge\boxed{(6 + 4)^3 - 1^8}$

$\huge\boxed{= 10^3 - 1^8}$

$\huge\boxed{10^3}$

$\huge\boxed{= 10\times10\times10}$

$\huge\boxed{= 100\times10 }$

$\huge\boxed{= 1,000}$

$\huge\boxed{1^{8}}$

$\huge\boxed{= 1\times1\times1 \times 1 \times 1 \times 1 \times 1 \times 1}$

$\huge\boxed{= 1 \times 1 \times 1 \times 1}$

$\huge\boxed{= 1\times1}$

$\huge\boxed{= 1}$

$\huge\boxed{1,000 - 1}$

$\huge\boxed{= 999}$

$\huge\text{Answer: \textsf{999}}$

$\huge\text{Good luck on your assignment \& enjoy your day!}$

~ $\huge\boxed{\frak{Amphitrite1040:)}}$

8 0

2 years ago