All categories

3 years ago

8y +9 > 41 please help im on a staar test.

Mathematics

2 answers:

hammer [34]3 years ago

6 0

Answer:

y>4

Step-by-step explanation:

8y+9>41

subtract 9

8y>32

divide by 8

y>4

Mrrafil [7]3 years ago

6 0

Answer:

y>4

Step-by-step explanation:

8y+9>41

subtract 9 from both sides

8y>32

divide 8 on both sides

y>4

You might be interested in

Solve equation. Show steps <br> 8+x=4x+2

statuscvo [17]

Answer:

x=2

Step-by-step explanation:

8 + x = 4x +2

Subtract 4x from both sides:

8 + x - 4x = 4x + 2 - 4x

Group like terms:

x - 4x + 8 = 4x + 2 -4x

Simplify the arithmetic:

-3x + 8 = 4x + 2 -4x

Group like terms:

-3 + 8 = 4x - 4x + 2

Simplify the arithmetic:

-3x + 8 = 2

8 0

3 years ago

Find the perimeter of shape ABCDE

EleoNora [17]

Answer:

Perimeter of a triangle = 2*(length + breadth)

SO = 2*18+41

= 77 is the perimeter

6 0

3 years ago

You need to buy 12 tickets to a weekend concert festival but have two options for where to purchase them. Concert Specialties se

AURORKA [14]

Answer:

Concert Specialties is the better buy

Step-by-step explanation:

In order to determine which of the two deals is the better buy, we first need to find out how many of each pack we would need to get the needed 12 tickets. Once we have this value we multiply it by the dollar amount of each pack and compare the totals like so...

Concert Specialties => pack of 3 * 4 = 12 tickets => 4 * 75 = $300

We 'R' Entertainment => pack of 4 * 3 = 12 tickets => 3 * 108 = $324

Therefore, we can now see that the Concert Specialties is the better buy since you are getting the 12 tickets for $24 less than We 'R' Entertainment

3 0

3 years ago

A cylindrical can without a top is made to contain 25 3 cm of liquid. What are the dimensions of the can that will minimize the

Basile [38]

Answer:

Therefore the radius of the can is 1.71 cm and height of the can is 2.72 cm.

Step-by-step explanation:

Given that, the volume of cylindrical can with out top is 25 cm³.

Consider the height of the can be h and radius be r.

The volume of the can is V= $\pi r^2h$

According to the problem,

$\pi r^2 h=25$

$\Rightarrow h=\frac{25}{\pi r^2}$

The surface area of the base of the can is = $\pi r^2$

The metal for the bottom will cost $2.00 per cm²

The metal cost for the base is =$(2.00× $\pi r^2$ )

The lateral surface area of the can is = $2\pi rh$

The metal for the side will cost $1.25 per cm²

The metal cost for the base is =$(1.25× $2\pi rh$ )

$=\$2.5 \pi r h$

Total cost of metal is C= 2.00 $\pi r^2$ + $2.5 \pi r h$

Putting $h=\frac{25}{\pi r^2}$

$\therefore C=2\pi r^2+2.5 \pi r \times \frac{25}{\pi r^2}$

$\Rightarrow C=2\pi r^2+ \frac{62.5}{ r}$

Differentiating with respect to r

$C'=4\pi r- \frac{62.5}{ r^2}$

Again differentiating with respect to r

$C''=4\pi + \frac{125}{ r^3}$

To find the minimize cost, we set C'=0

$4\pi r- \frac{62.5}{ r^2}=0$

$\Rightarrow 4\pi r=\frac{62.5}{ r^2}$

$\Rightarrow r^3=\frac{62.5}{ 4\pi}$

⇒r=1.71

Now,

$\left C''\right|_{x=1.71}=4\pi +\frac{125}{1.71^3}>0$

When r=1.71 cm, the metal cost will be minimum.

Therefore,

$h=\frac{25}{\pi\times 1.71^2}$

⇒h=2.72 cm

Therefore the radius of the can is 1.71 cm and height of the can is 2.72 cm.

6 0

3 years ago

TRIGONOMETRY , can you solve this plz:(<br>even if you know one of them,plz help:)

daser333 [38]

Answer:

See below

Step-by-step explanation:

$\frac{1}{1-cos A} - \frac{1}{1+cos A} =2 cosec A cot A \\ \\ L. H. S.= \frac{1}{1-cos A} - \frac{1}{1+cos A} \\ \\ = \frac{1+cos A - (1 - cos A)}{(1-cos A)(1+cos A)}\\ \\ = \frac{1+cos A - 1 + cos A}{1-cos^{2} A}\\ \\ = \frac{2cos A }{sin^{2} A}\\ \\ =2 .\frac{1}{sin A}.\frac{cos A }{sin A}.\\ \\ = 2.cosec \: A.cot \: A \\ \\ = R.H.S$

5 0

3 years ago