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Misha Larkins [42]
3 years ago
6

4х + Зу = 3 4x - 2y = 18 How to solve this?

Mathematics
1 answer:
Brilliant_brown [7]3 years ago
5 0

Using elimination, you can do

4x+3y-(4x-2y)=3-(18)

5y=-15

y=-3

Substitute it back into original equation:

4x+6=18

4x=12

x=3

<h2>So, the answer is <u><em>x=3, y=-3</em></u></h2>

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Answer:

a) Hence the equation of the sinusoidal function that describes the height of the shorts in terms of time is y = 9 + 7* sin(\pi * t / 15 - \pi  / 6)

b) Hence the height of the shorts at exactly t = 10 minutes, to

the nearest tenth of a meter is 5.5 meters

Step-by-step explanation:

a) The wind turbine blade traverses a circular path as it rotates with time (t), whose time variation is given by the following trajectory equation :

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R = (16 m - 2 m)/2 (since diameter = maximum height - minimum height of the pink short)

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= 7 m (radius of the circle)

Also, center of the circle will be at (0, 2 + R) i.e (0,9)

So,  is the trajectory path equation to the circle

Let x = 7* cos(w*t + \phi ) & y = 9 + 7* sin(w* t + \phi) be the parametric form of the above circle equation which represent the position of the pink shorts at the tip of the blade at time t  

At t= 10s, y = 16 m so we have,

9 + 7 * sin(10* w + \phi) = 16 ---------------(1)

Also, at t= 25s, y =2 m so we have,

9 + 7* sin(25 * w +\phi) = 2--------------(2)

Solving we have, 10* w + \phi = \pi/2 & 25*w + \phi = 3*pi/2

15* w = \pi\\\\w = \pi/15 & \phi = \pi/2 - 10*\pi/15 = -\pi / 6  

Therefore y = 9 + 7* sin(\pi * t / 15 - \pi  / 6) is the instantaneous height of the pink short at time t ( in seconds)

b) At t= 10minutes = 10 * 60 s = 600s, we have,

y = 9 + 7 * sin(\pi * 600/15 - \pi / 6)\\\\= 9 + 7 * sin(40* \pi - \pi / 6)

= 5.5 meters (pink short will be at 5.5 meters above ground level at t= 10 minutes)

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