The answer is d :) hope it helps
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The length of the line AB as described by points A and B in the task content is; √125.
<h3>What is the length of the line?</h3>
a) The length of AB as described is;
AB = √((7-2)² + (4-(-6))²)
AB = √(25 + 100) = √125.
b) The slope of AB is;
Slope, m = (7-2)/(4-(-6)) = 5/10
Slope = 1/2.
c). The coordinates of the midpoint of AB are;
x = (4+(-6))/2 = -1
y = (7+2)/2 = 4.5
The midpoint is; (-1, 4.5).
2) The radius of the circle as described with centre (0, 0) that passes through the point (5, –3) is;
Radius = √((5-0)² + (-3-0)²)
Radius = √(25+9) = √34 = 5.8
3) Hence, the equation of a circle with centre (0, 0) that passes through the point (5, –3) is;
(x-5)² + (x-3)² = 5.8².
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Answer:
Horizontal distance, d = 9.146
Step-by-step explanation:
The given function is
The horizontal distance, d, is the distance on ground. So, set f(d) = 0.
That is, a height of zero which becomes the ground level.
Using the quadratic formula:
Thus, the ball is in air between d=-0.146 to d=9.146.
Since the distance can not be negative, the ball remains in the air between d = 0 to d = 9.146.
Therefore d = 9.146