Solve for y. A. 90° B. 115° C. 108° D. 130°
2 answers:
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The equation to finding the area of a triangular prism is 1/4*height
-a^4 + 2 * (a*b)^2 + 2(a*c) - b^4 + 2(b*c)^2 - c^4. (I know that's really confusing)
The A, B, and C values all stand for the base side lengths of the 2 triangles. The h is height. Plug in these values to the equation, and your answer is 3436.4 yards cubed. I hope this helped.
The A, B, and C values all stand for the base side lengths of the 2 triangles. The h is height. Plug in these values to the equation, and your answer is 3436.4 yards cubed. I hope this helped.
Answer:
z = 6
Step-by-step explanation:
We know that ...
sin(x) = cos(90 -x)
Substituting (9z-1) for x, this is ...
sin(9z -1) = cos(90 -(9z -1))
But we also are given ...
sin(9z -1) = cos(6z +1)
Equating the arguments of the cosine function, we have ...
90 -(9z -1) = 6z +1
90 = 15z . . . . . . . . . add (9z-1) to both sides
6 = z . . . . . . . . . . . . divide by 15
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<em>Comment on the graph</em>
The attached graph shows 5 solutions in the domain of interest. These come from the fact that the relation we used is actually ...
sin(x) = cos(90 +360k -x) . . . . . for any integer k
Then the above equation becomes ...
90 +360k = 15z
6 +24k = z . . . . . . . . . for any integer k
The sine and cosine functions also enjoy the relation ...
sin(x) = cos(x -90)
sin(9z -1) = cos(9z -1 -90) = cos(6z +1)
3z = 92 . . . . . equating arguments of cos( ) and adding 91-6z
z = 30 2/3
