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Vikki [24]
3 years ago
15

Using the triangle below, set up and solve an equation in order to find the value of x.

Mathematics
2 answers:
GarryVolchara [31]3 years ago
8 0
180 degrees - 118 degrees - 34,6 degrees = 27, 4 degrees

Since the interior angles of a triangle sum up to 180 degrees.

Hope it helps!✨
dybincka [34]3 years ago
8 0

Answer:

x = 180 - 118 - 34.6 = 27.4

Step-by-step explanation:

The sum of the internal angles of each type of (2D) polygon will only have 1 specific value for each polygon. In the case of a triangle, the interior angles add up to 180 degrees.

Using a statement-reason approach, we start by saying:

Q^ + R^ + S^ = 180 degrees  (*)                 Interior angles of a triangle = 180

(*Please use proper notation if you were already taught it - these computer keyboards can only do so much you know...)

Then you just solve normally for x:

34.6 + 118 + x = 180

x = 180 - 118 - 34.6

x = 27.4 degrees

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Solve the equation equations by using completing the square method
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Answer:

Answer:

Step-by-step explanation:

(a) 4x2 -- 3x - 2 = 0

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(a) 4x2 -- 3x - 2 = 0

x1,2 = -b ± √b²- 4ac

         ---------------------

                  2a

    x1,2  = 3 ±√41

             --------------

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(b) (2x - 3)2 = 6​

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5 0
3 years ago
Stress at work: In a poll conducted by the General Social Survey, 80% of respondents said that their jobs were sometimes or alwa
Svet_ta [14]

Answer:

a) P=0.019

b) P=0.263

c) P=0.794

Step-by-step explanation:

We assume that the poll gives the population's proportion of respondents said that their jobs were sometimes or always stressful (p=0.8).

Then, a sample of size n=190 is taken.

The sample mean is:

\mu=np=190*0.8=152

The sample standard deviation is:

\sigma=\sqrt{np(1-p)}=\sqrt{190*0.8*0.2}=\sqrt{30.4}=5.514

The probability that 140 or fewer workers find their jobs stressful is:

z=(X-\mu)/\sigma=(140.5-152)/5.514=-11.5/5.514=-2.08 \\\\P(X\leq140)=P(X

Note: a correction for continuity is applied.

The probability that more than 155 workers find their jobs stressful is

z=(X-\mu)/\sigma=(155.5-152)/5.514=3.5/5.514= 0.635 \\\\P(X>155)=P(X>155.5)=P(z>0.635)=0.263

The probability that the number of workers who find their jobs stressful is between 145 and 158 inclusive is:

z_1=(X_1-\mu)/\sigma=(158.5-152)/5.514=6.5/5.514= 1.179\\\\  z_2=(X_2-\mu)/\sigma=(144.5-152)/5.514=-7.5/5.514= -1.360 \\\\ P(145\leq X\leq 158)=P(144.5< X< 158.5)\\\\P(145\leq X\leq 158)=P(X

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Hope this helped:)
7 0
4 years ago
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