Answer: the first stage of any proposed DTP project should be organization and design.
Explanation:
The options to the question include:
A. Desktop Publishing is one way to become acquainted with a new business audience.
B. computer software is continually being refined to produce high quality printing.
C. the first stage of any proposed DTP project should be organization and design.
D. the planning stage of any DTP project should include talking with the intended audience.
The paragraph best supports the statement that the first stage of any proposed DTP project should be organization and design.
This can be infered from the statement that "Before you begin, you should know your intended audience, the message you want to communicate, and what form your message will take".
Hey there!
Backlighting in photography is when the primary light source is located behind the subject. Most of the time, photos that rely on backlighting to not reveal any details of the front of the subject and only show a silhouette instead. So, this is false, since you will not be able to see any detail of the front of the object you are photographing.
Hope this helped you out! :-)
Answer:
The pseudocode is given below
Explanation:
<u>Pseudocode</u>
- Prompt user to enter string
- Pass it to combination function which will calculate the total combination and will return it in array
- In combination method -
- Check if the string is length 2 size ie of 0 or 1 length then return string itself
- Else iterate through string user entered
- Get the current character in variable and check if the variable is already used than skip
- Create a string from 0 to ith index + (concatencate) i+1 to length and recursive call combination function and pass this string and store result in subpermutation array
- For each recursive call push character + subPermutation in totalArrangement array .
255.255.240.0 is a /20 subnet mask, therefore there are 4 borrowed bits (from the 3rd octet). Number of hosts on each subnetwork = (2 to the power 4) - 2 (i.e. 4 bits in host portion of address), which gives 14. So I got 16 subnetworks, and 14 hosts on each subnetwork.1
