Answer:
Answer is A. One.
Refer below.
Explanation:
A data flow cannot go directly back to the same process it leaves. There must be at least one other process that handle(s) the data flow, produce(s) some other data flow, and return(s) the original data flow to the beginning process.
The Computer Fraud and Abuse Act I believe. Sorry if I’m wrong and I hope that it helps :)
Answer:
See Explaination
Explanation:
#include <iostream>
#include <string.h>
using namespace std;
char *mixem(char *s1, char *s2);
int main() {
cout << mixem("abc", "123") << endl;
cout << mixem("def", "456") << endl;
return 0;
}
char *mixem(char *s1, char *s2) {
char *result = new char[1 + strlen(s1) + strlen(s2)];
char *p1 = s1;
char *p2 = s2;
char *p = result;
while (*p1 || *p2) {
if (*p1) {
*p = *p1;
p1++;
p++;
}
if (*p2) {
*p = *p2;
p2++;
p++;
}
}
*p = '\0';
return result;
}
