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Nataly [62]
3 years ago
9

Ns of

Mathematics
1 answer:
motikmotik3 years ago
5 0

Answer:

y=3x2^x

Step-by-step explanation:

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2 is 4% of what number?
kaheart [24]
x-searched\ number\\\\4\%x=2\\\\0.04x=2\ \ \ \ |:0.04\\\\x=50\\\\2\ is\ 4\%\ of\ 50
6 0
3 years ago
The volume of a cone is 1540cm³. If its radius is 7cm, calculate the height of the cone. (Take pi = 22/7)
Ann [662]

Answer:

h=30

Step-by-step explanation:

Volume of a cone=1540cm^{3}, Radius=7cm.

The height of a cone=h

When we need to find the height of a cone, we can use the formula of the volume of a cone, which is \frac{1}{3} \pi r^{2} h to find the height of a cone.

1540cm^{3} =\frac{1}{3}\pi r^{2}  h

Put the pi value=22/7 and the value of radius which is 7 cm into the formula.

1540cm^{3}=\frac{1}{3}*\frac{22}{7}  7^{2}h

1540cm^{3} =\frac{154}{3}h

Move \frac{154}{3} to another side. 1540 divided by  \frac{154}{3} to calculate what is the value of h, h is the height of a cone. Like this.

\frac{1540cm^{3} }{\frac{154}{3} } =h

30=h

Rearrange the h.

h=30

I hope you will understand my solution and explanation. If you still cannot get the point, you can ask me anytime! Thank you!

4 0
3 years ago
Read 2 more answers
7b + 3 – 4b = 3 – 3(b + 4)
svlad2 [7]

Hello from MrBillDoesMath!

Answer:  b

Discussion:

7b + 3 - 4b = 3 - 3(b+4)  =>

7b + 3 - 4b = 3 - 3b -12 =>

(7b - 4b) + 3   = -3b - 9 =>

3b + 3 = -3b -9    =>      Add 9 to both sides

3b + 12 = -3b -9 + 9  =>

3b + 12 = -3b  =>         ( add 3b to both sides)

6b + 12 = 0 =>             (subtract 12 from both sides)

6b = -12 =>

b = -12/6 = -2


Thank you,

MrB


7 0
3 years ago
If DC = 10 centimeters, SR = 15 centimeters, and the area of ABCD is 72 square centimeters, then the area of PQRS is square cent
Dovator [93]
I think this will help you

3 0
3 years ago
In two or more complete sentences describe how to determine the appropriate model for the set of data. (1, 1), (3, 2), (6, 3), (
Dafna1 [17]

Answer:

3,2

Step-by-step explanation:

hope you like it then comment

5 0
3 years ago
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