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3 years ago

Need help on the first one! Thank you :)

Mathematics

1 answer:

Radda [10]3 years ago

7 0

Answer:

y10 and x2 (I think).

Step-by-step explanation:

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Part Two: Find they<br> 5. y= 4x + 3

skelet666 [1.2K]

Answer:

divide 4. from 4 n 3. 3 divided by 4 answer us the answer fir x and then you times that answer to 4 and that is the answer for y

7 0

3 years ago

Find a particular solution to the nonhomogeneous differential equation y??+4y?+5y=?10x+e^(?x).

Firdavs [7]

Answer:

A) Particular solution:

$2x+\frac{1}{2}e^{-x}-\frac{8}{5}$

B) Homogeneous solution:

$y_{h}=e^{-2x}(c_{1}cos(x)+c_{2}sin(x))$

C) The most general solution is

$y=e^{-2x}(c_{1}cos(x)+c_{2}sin(x))+2x+\frac{1}{2}e^{-x}-\frac{8}{5}$

Step-by-step explanation:

Given non homogeneous ODE is

$y''+4y'+5y=10x+e^{-x}---(1)$

To find homogeneous solution:

$D^{2}+4D+5=0\\D^{2}+4D+4-4+5=0\\\\(D+2)^{2}=-1\\D+2=\pm iD=-2 \pm i\\y_{h}=e^{-2x}(c_{1}cos(x)+c_{2}sin(x))---(2)$

To find particular solution:

$y_{p}=Ax+B+Ce^{-x}\\\\y'_{p}=A-Ce^{-x}\\y''_{p}=Ce^{-x}\\$

Substituting $y_{p},y'_{p},y''_{p}$ in (1)

$y''_{p}+4y'_{p}+5y_{p}=10x+e^{-x}\\Ce^{-x}+4(A-Ce^{-x})+5(Ax+B+Ce^{-x})=10x+e^{-x}\\$

Equating the coefficients

$5Ax+2Ce^{-x}+4A+5B=10x+e^{-x}\\5A=10\\A=2\\4A+5B=0\\B=-\frac{4A}{5}B=-\frac{8}{5}2C=1\\C=\frac{1}{2}\\So,\\y_{p}=2x+\frac{1}{2}e^{-x}-\frac{8}{5}---(3)\\$

The general solution is

$y=y_{h}+y_{p}$

from (2) ad (3)

$y=e^{-2x}(c_{1}cos(x)+c_{2}sin(x))+2x+\frac{1}{2}e^{-x}-\frac{8}{5}$

6 0

3 years ago

In ∆ KLM above, NO // ML and < KNO = < KON. Find m < MNL =

4vir4ik [10]

Answer: In ∆ KLM above, NO // ML and < KNO = < KON. Find m < MNL =

Step-by-step explanation: dUNNO

6 0

3 years ago

Is y=x a proportional linear equation

Dmitry [639]

Answer: yes.

Step-by-step explanation:

7 0

3 years ago

Read the following and answer the questions that follow.

user100 [1]

Answer:

Step-by-step explanation:

(7/12) of 840 attended the concert:

(7/12)*(840) = 490 students attended the Spring Concert.

(840 - 490) = 350 did not attend

(350/840) is the fraction of students who did not attend. This can be reduced to (35/84)

(350/840) = 0.4167 or 41.67% did not attend.

3 0

2 years ago