This problem is a combination of the Poisson distribution and binomial distribution.
First, we need to find the probability of a single student sending less than 6 messages in a day, i.e.
P(X<6)=P(X=0)+P(X=1)+P(X=2)+P(X=3)+P(X=4)+P(X=5)
=0.006738+0.033690+0.084224+0.140374+0.175467+0.175467
= 0.615961
For ALL 20 students to send less than 6 messages, the probability is
P=C(20,20)*0.615961^20*(1-0.615961)^0
=6.18101*10^(-5) or approximately
=0.00006181
Answer:
Step-by-step explanation:
If x is the white dot on the graph:
From what it looks like, x is right between -35 and -34 x (which is -35.5).
If that is the case then none of the answers are correct since -35.5 is <u>equal or less</u> than x. (the sign looks like this: "
" )
But if you have to choose one of the answers then number 4 (-35.5 < x) would be closest.
P(even or add).
I hope i helped!
If so, Please mark as brainliest!
The answer is 0.6, 5 or higher add one more, 4 or less stays the same