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Aleks [24]
2 years ago
14

4x - 6y =12 make this slope intercept from

Mathematics
1 answer:
Mekhanik [1.2K]2 years ago
8 0
Y= 2/3 x -2

Hope this helps
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Plz help I have a time test
Alex17521 [72]

Answer:

c

Step-by-step explanation:

8 0
2 years ago
How much must be added to each of the three numbers 1, 11, and 23 so that together they form a geometric progression?
Sliva [168]

Answer:

49

Step-by-step explanation:

Let x be unknown number which should be added to numbers 1, 11, 23 to get geometric progression. Then numbers 1 + x, 11 + x, 23 + x are first three terms of geometric progression.

Hence,

b_1=1+x\\ \\b_2=11+x\\ \\b_3=23+x

and

b_2=b_1\cdot q\Rightarrow 11+x=(1+x)q\\ \\b_3=b_2\cdot q\Rightarrow 23+x=(11+x)q

Express q:

q=\dfrac{11+x}{1+x}=\dfrac{23+x}{11+x}

Solve this equation. Cross multiply:

(11+x)^2=(1+x)(23+x)\\ \\121+22x+x^2=23+x+23x+x^2\\ \\121+22x=23+24x\\ \\22x-24x=23-121\\ \\-2x=-98\\ \\2x=98\\ \\x=49

5 0
2 years ago
PLEASE HELP ME!!!!! <br><br> what is the perimeter and area of this figure?
Pavel [41]

Answer:

The perimeter is 99

Step-by-step explanation:

you do 11x9=99

4 0
3 years ago
Find the ratio y:x, if 3x=11y,
Aleks [24]

Answer:

3:11

Step-by-step explanation:

3x=11y

<u>Rearrange to the format of the ratio.</u>

11y = 3x

<u>Let's find </u><u>y/x</u><u>. </u><u>y/x</u><u> is </u><u>y:x.</u>

11y = 3x

<u>Divide both sides by </u><u>11</u><u>.</u>

11y/11 = 3x/11

y = 3x/11

<u>NOW LET'S DIVIDE BOTH SIDES BY </u><u>x</u><u> TO GET </u><u>x</u><u> AS THE DENOMINATOR OF </u><u>y</u><u>.</u>

y = 3x/11

y/x = (3x/11)/x

y/x = (3x/11) * 1/x

y/x = 3/11

Therefore, y:x = 3:11

Please thank, rate 5 stars, and give brainliest. Thank you.

7 0
3 years ago
Find the center and radius of the circle whose equation is x 2 + y 2 + 10x − 1
Margaret [11]

we conclude that the center of the circle is the point (-5, 0).

<h3>How to find the center of the circle equation?</h3>

The equation of a circle with a center (a, b) and a radius R is given by:

(x - a)^2 + (y - b)^2 = R^2

Here we are given the equation:

x^2 + y^2 + 10x - 1 = 0

Completing squares, we get:

x^2 + 10x + y^2 = 1

Now we can add and subtract 25 to get:

x^2 + 10x + 25 - 25 + y^2 = 1\\\\(x + 5)^2 -25 + y^2 = 1\\\\(x + 5)^2 + (y - 0)^2 = 26

Comparing that with the general circle equation, we conclude that the center of the circle is the point (-5, 0).

If you want to learn more about circles:

brainly.com/question/1559324

#SPJ1

3 0
2 years ago
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