4x - 6y =12 make this slope intercept from

OleMash [197]

Answer:

x = 3.87

Step-by-step explanation:

Using the right angle altitude theorem, we know that all three triangles are congruent, so the lengths of corresponding sides of the triangles are in proportion..

AD/DB = DB/DC

15/x = x/1

x² = 15

x = √15

x = 3.87

8 0

2 years ago

Write the equation of a line in slope-intercept form that goes through the points

Stella [2.4K]

Answer: The equation in slope-intercept form is y=2x-11

Step-by-step explanation: Slope-intercept is y=mx+b where m is the slope and b is the y-intercept. To find the slope, you find the difference between the y values divided by the difference between the x values. -5-(-9) = 4, and 3-1 is 2. 4/2 is 2, so m = 2. Since the slope is 2, it states for every x you move on the right you move 2 up. But we are trying to get the y-intercept, so x = 0. We are subtracting 1 in our x value, so we move 2 downwards. We subtract 2 from -9 which gives us -11, which is our y-intercept.

Hope this helps!

5 0

3 years ago

Could someone help me and explain?

ExtremeBDS [4]

Answer:

length 3 in
width 2 in

Step-by-step explanation:

Since none of the answer choices match the drawing of the gardener, we assume the question is referring to the drawing of the partner.

The gardener's drawing is 1/4 of actual size. So, in terms of the gardener's drawing, actual size is ...

gardener's drawing = (1/4)actual size

actual size = 4(gardener's drawing)

__

The partner's drawing is 1/20 of actual size, so is ...

partner's drawing = actual size/20 = (4(gardener's drawing))/20

partner's drawing = (4/20)(gardener's drawing)

partner's drawing = (gardener's drawing)/5

__

Then the {length, width} of the partner's drawing are ...

partner's drawing {length, width} = {15 in, 10 in}/5 = {3 in, 2 in}

The partner's drawing has a length of 3 inches and a width of 2 inches.

6 0

3 years ago

Its an easy 25 points

boyakko [2]

Answer:

hope it's help u thank u

Step-by-step explanation:

y=-8
y=-5
y=1
y=10

8 0

2 years ago

A 15 ft. telephone pole has a wire that extends from the top of the pole to the ground. The wire and the ground form a 42° angle

Lorico [155]

Answer:

Correct choice is A

Step-by-step explanation:

Consider right triangle ABC formed by the telephone pole (side AB) and ground (side BC). In this triangle AC is the length of the wire, BC is the distance from the base of the pole to the spot where the wire touches the ground and AB=15 ft, ∠ACB=42°.

Then

$\sin 42^{\circ}=\dfrac{AB}{AC}\Rightarrow AC=\dfrac{AB}{\sin 42^{\circ}}=\dfrac{15}{\sin 42^{\circ}}\approx 22.4\ ft.$
$\tan 42^{\circ}=\dfrac{AB}{BC}\Rightarrow BC=\dfrac{AB}{\tan 42^{\circ}}=\dfrac{15}{\sin 42^{\circ}}\approx 16.7\ ft.$

8 0

3 years ago