Answer:
Please refer to the attachment
Answer:
Margin of error = 4.21 ounces
Step-by-step explanation:
According to the Question,
- Given That, You measure 25 turtles' weights, and find they have a mean weight of 31 ounces. Assume the population standard deviation is 12.8 ounces
Therefore, Sample mean = 31 ounces , Sample size(n) = 25 , Alpha(α) = 0.10 & Population standard deviation(σ) = 12.8 ounces
- Thus, Margin of error =
× σ / √n (
at α=.010 is 1.645)
Putting The Values, We get
1.645 × (12.8 / √25 ) ⇒ 4.2112 ≈ 4.21
Thus, the maximum margin of error associated with a 90% confidence interval for the true population mean turtle weight is 4.21 ounces
Answer:
Step-by-step explanation:
Like terms have same variable with same power. Combine like terms
153y³ + 132y² + 6y - 5 - 3y³ - 5y² +4y - 2
= <u>153y³ - 3y³</u> + 132y² - 5y² + 6y + 4y <u> -5 - 2</u>
= <u>150y³</u> + 127y² + 10y<u> - 7</u>
Answer:
D. is the answer
Step-by-step explanation:
It would be 10 as translating the line doesn't make it bigger or smaller<span />