Find the values of (625) ^-1/4

Mathematics

2 answers:

weeeeeb [17]2 years ago

8 0

Answer:

can whoevers watching help me eith my math

Step-by-step explanation:

im awful amd my questions are on my profile and i got a 50 before and this is my last attemp pplz

Rashid [163]2 years ago

4 0

Answer:

1) $625^-\frac{1}{4}$

=> $(5^4)^-^\frac{1}{4}$

=> (4 and 4 get simplified so we are left with 5 raised to the power-1)

=> $5^-^1$

=> $(a^m)^n =a^m^n$

=> $a^-^n=\frac{1}{a} ^n$

=> $\frac{1}{5}$

Step-by-step explanation:

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Assoli18 [71]

Answer:

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2 years ago

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A box in a supply room contains 24 compact fluorescent lightbulbs, of which 8 are rated 13-watt, 9 are rated 18-watt, and 7 are

Marrrta [24]

Answer:

a) There is 17.64% probability that exactly two of the selected bulbs are rated 23-watt.

b) There is a 8.65% probability that all three of the bulbs have the same rating.

c) There is a 12.45% probability that one bulb of each type is selected.

Step-by-step explanation:

There are 24 compact fluorescent lightbulbs in the box, of which:

8 are rated 13-watt

9 are rated 18-watt

7 are rated 23-watt

(a) What is the probability that exactly two of the selected bulbs are rated 23-watt?

There are 7 rated 23-watt among 23. There are no replacements(so the denominators in the multiplication decrease). Then can be chosen in different orders, so we have to permutate.

It is a permutation of 3(bulbs selected) with 2(23-watt) and 1(13 or 18 watt) repetitions. So

$P = p^{3}_{2,1}*\frac{7}{24}*\frac{6}{23}*\frac{17}{22} = \frac{3!}{2!1!}*\frac{7}{24}*\frac{6}{23}*\frac{17}{22} = 3*\frac{7}{24}*\frac{6}{23}*\frac{17}{22} = 0.1764$