see the attached figure to better understand the problem
we know that
In a parallelogram opposite angles are congruent, and consecutive angles are supplementary
So
in this problem
∠Y=
°
∠W=∠Y
∠W=°
∠Z=∠X
∠Y+∠Z=
°
∠Z=
∠Z=
°
∠X=∠Z
∠X=°
therefore
the answer is
∠Y=°
∠W=°
∠X=°
∠Z=°
The surface charge density:
S(igma) = Q / A
A = 1.6 * 10^(-2) * 1.6 * 10^(-2) = 2.56 * 10^(-4) m²
The electric field: E = S / E(psilon) o
E = 0.711 * 10^^(-9) / ( 2.56 * 10 ^(-4) * 8.85 * 10 ^(-12) ) =
= 0.3138 * 10 ^6 = 3.138 * 10^5 V/m
a ) Δ V = E d
Δ V = 3.138 * 10^5 V/m* 1.2 * 10^(-3) m = 376.56 V
b ) When d = 2.40 mm:
Δ V = 3.138 * 10^5 V/m * 2.40 *10^(-3) m = 753.12 V
Answer:
-8.88888888889.............
we have to find equation similar to
Firstly , we can divide both sides by 2
now, we can multiply both sides by 3
we get
............Answer
