How many grams of aluminum are required to produce 3. 5 moles al2o3.
1 answer:
Answer:
189 g of Aluminum
Explanation:
3.5 moles of Al2O3 has a total mass of 357 g roughly. There is 189 g of Aluminum, and 168 g of Oxygen which adds up to 357 g of Al2O3.
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