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xxMikexx [17]
3 years ago
15

In chemistry class 18 liters of 30% alcohol solution must be mixed with 20% solution to get 14% solution how many liters of 20%

solution are needed?
Mathematics
1 answer:
alexdok [17]3 years ago
5 0
If you are mixing a 30% solution with a 20% solution to obtain a 14% solution, you will never obtain a 14% solution.

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Factor the expression 3x? - 75 completely. (select one answer)
AysviL [449]
Should be the 3rd one
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Lana has 3 bags with the same amount of marbles in them, totaling 12 marbles. Markus has 3 bags with the same amount of marbles
Julli [10]

Answer:

Markus has 6 marbles in each bag.

Step-by-step explanation:

Markus has 18 marbles and 3 bags

If you divide 18 marbles by 3 bags that would be 6 marbles in each bag.

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A particular psychological test is used to measure need for achievement. The average test score for all university students in O
Angelina_Jolie [31]

Answer:

Only B and C are always true.

Step-by-step explanation:

To analyse which statements are always true, we go through the process of finding confidence intervals for sample means, from the start.

Confidence Interval = (Sample mean) ± (Margin of error)

From this expression, it is evident that the margin of error determines how wide the confidence interval would be.

Sample Mean = 110 (given)

Margin of Error = (Critical value) × (Standard deviation of the distribution of sample means)

Since no information about the population standard deviation is provided, the critical value is obtained using t-distribution.

The critical value usually varies at different confidence levels and degree of freedoms.

The higher the confidence level, the higher the critical value and the higher the margin of error leading to a wider range.

Hence, a confidence interval of 95% will have a higher critical value than a confidence interval of 90%. Hence, statement C is proved once that 'for n = 100, the 95% confidence interval will be wider than the 90% confidence interval'.

After obtaining the critical value, we then obtain the standard deviation of the distribution of sample means or simply the standard error of the mean. This is given as

σₓ = σ/√n

where σ = standard deviation; which isn't given. The standard deviation might be high enough to guarantee that the Margin of error is high too for the confidence interval to contain 115 or low enough to ensure that the Margin of error is very small and the confidence interval will not contain 115.

Or the sample size might be high enough to make the standard error of the mean to be eventually small and lead to a small margin of error and the condidence interval will not contain 115.

The point is, it isn't always sure that the resulting interval.would contain 115. So, statement A isn't always true.

Then from σₓ = σ/√n,

n = sample size, a large sample size means a more narrow confidence interval and a small sample size means a wider sample size. This proves statement C.

The 95% confidence interval for n = 100 will be more narrow than the 95% confidence interval for n = 50.

Hence, Only B and C are always true.

Hope this Helps!!!

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3 years ago
A pool has a depth of 12 feet and a width of 14 feet.If it holds 1680 cubic feet of water, what is the length of the pool?
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12 x 14 x L = 1680

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