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Ierofanga [76]
3 years ago
8

A 95% confidence interval for an unknown population mean is given by (9, 12). How should this confidence interval be interpreted

?
A) There is a 95% chance the sample mean = 10.5 is within 3 units of the true mean . B) There is a 95% chance the sample mean = 10.5 is within 1.5 units of the true mean .
C) There is a 95% chance the true mean is within 1.5 units of the sample mean = 10.5.
D) There is a 95% chance the true mean is within 1.5 standard deviations of the sample mean = 10.5.
Mathematics
1 answer:
Zanzabum3 years ago
8 0
C is my answer of ask other sources tho. Ok
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Hello I don’t understand question 9 a and b. Please show working out.<br> Thanks
brilliants [131]
A) I would make the positive integer x and then form an equation.

x + 30 = x^2 - 12
x + 42 = x^2
0 = x^2 - x - 42 this can be factorised
(x - 7) ( x + 6) Therefore x = 7 or x = -6

Since the question asks for a positive integer the answer is 7.

B) two positive numbers x and y.

X - y = 3
x^2 + y^2 = 117

Use these simultaneous equations to figure out each number.

Rearrange the first equation

x = y + 3

Then substitute it into the second equation.

(y+3)^2 + y^2 = 117
y^2 + 6y + 9 + y^2 = 117
2y^2 + 6y - 108 = 0
then factorise this.
(2y - 12) (y + 9)

This means that y = 6 or y = -9 but it’s 6 because that’s the only positive number.

Use y to find x

x = y + 3
x = 6 + 3
x = 9

So the answers are x = 9 and y = 6.
3 0
3 years ago
A national survey indicated that 50​% of adults conduct their banking online. It also found that 20​% are younger than​ 50, and
Arisa [49]

Answer:

The probability that a person is younger than 50 given that she uses onling banking is 1.5%

Step-by-step explanation:

The survey indicated that 50% of adults conducts their banking online.

P(online banking customers) =1/2

Of the total number of customer that bank online, the survey stated that 20% of them are younger than 50 years.

P(customers younger than 50 yrs) =1/5

Out of the 20% than are younger than 50, we were told that 15% of them conduct online banking.

P(younger than 50 online banking customer) =3/20

Therefore the the probability that a = person is younger than 50 given that she uses online banking is  P = 3/20*1/5*1/2 =17==3/200 = 0.015 =1.5%

The probability that she is younger than 50 does not increase or decrease with additional information, it only makes it clearer.

3 0
4 years ago
Find each missing length to the nearest tenth. (Using Pythagorean Theorem)​
irinina [24]

Answer:

7) 8.9

8) 6.7

9) 12.2

10) 7.6

11) 7.3

12) 6.3

Step-by-step explanation:

8 0
4 years ago
An arrow is launched upward with a velocity of
anyanavicka [17]

Answer:

Step-by-step explanation:

The velocity of the arrow when it was launched upwards is 320 feet per second. The height of the platform from which it was launched is 50 ft

This means that the arrow is already 50 feets from the ground before moving upwards.

The height that it attains on moving from 50 feets will be determined by Newton's formula of motion.

v^2 = u^2 + 2as

u = initial velocity = 320 feet per second.

1 feet per second = 0.305 meters per second

320 feet per second = 320× 0.305

= 97.6 feets per second

a = acceleration due to gravity =

- 32.17405 feet/second^2 because the arrow is moving upwards)

s =maximum height of the arrow

v = final velocity = 0 feet/second

Substituting into the equation,

0^2 = 97.6^2 + 2×- 32.17405 × s

0 = 9525.76 - 64.3481s

64.3481s = 9525.76

s = 9525.76/64.3481 = 148.03 feets

Total height from the ground would be

148.03 + 50 = 198.03 feets

5 0
3 years ago
I just need a quick explanation pls and thank you!
mars1129 [50]

Answer:

see below

Step-by-step explanation:

Well there are two main reasons

1. exponential functions don't have a negative value, i mean

f(x)\neq -something

2. well exponential functions are like a curve, the firsts values are very close to each other, but then they start jumping like mad (translate it to your own words), for example in

f(x) = x^2

the first positive values are

1,2,9 but then 16,25,36,49

3 0
3 years ago
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