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Ierofanga [76]
3 years ago
8

A 95% confidence interval for an unknown population mean is given by (9, 12). How should this confidence interval be interpreted

?
A) There is a 95% chance the sample mean = 10.5 is within 3 units of the true mean . B) There is a 95% chance the sample mean = 10.5 is within 1.5 units of the true mean .
C) There is a 95% chance the true mean is within 1.5 units of the sample mean = 10.5.
D) There is a 95% chance the true mean is within 1.5 standard deviations of the sample mean = 10.5.
Mathematics
1 answer:
Zanzabum3 years ago
8 0
C is my answer of ask other sources tho. Ok
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If √3 = 1.732, then √[(√3-1)/(√3+1)] is equal to​
adelina 88 [10]

Step-by-step explanation:

<h3><u>Given Question :-</u></h3>

\sf \:  \sqrt{3} = 1.732, \: then \:  \sqrt{\dfrac{ \sqrt{3}  - 1}{ \sqrt{3}  + 1} }

\red{\large\underline{\sf{Solution-}}}

Given expression is

\rm :\longmapsto\: \sqrt{\dfrac{ \sqrt{3}  - 1}{ \sqrt{3}  + 1} }

<em>On rationalizing the denominator, we get </em>

\rm \:  =  \:  \sqrt{\dfrac{ \sqrt{3}  - 1}{ \sqrt{3}  + 1}  \times \dfrac{ \sqrt{3}  - 1}{ \sqrt{3}  - 1} }

\rm \:  =  \:  \sqrt{\dfrac{ {( \sqrt{3}  - 1)}^{2} }{( \sqrt{3}  + 1)( \sqrt{3}  - 1)} }

<em>We know, </em>

\boxed{ \tt \: (x - y)(x + y) =  {x}^{2} -  {y}^{2} \: }

<em>So, using this, we get </em>

\rm \:  =  \: \dfrac{ \sqrt{3}  - 1}{ \sqrt{ {( \sqrt{3})}^{2}  -  {(1)}^{2} } }

\rm \:  =  \: \dfrac{ \sqrt{3}  - 1}{ \sqrt{ 3 - 1} }

\rm \:  =  \: \dfrac{ \sqrt{3}  - 1}{ \sqrt{2} }

\rm \:  =  \: \dfrac{ \sqrt{3}  - 1}{ \sqrt{2} } \times \dfrac{ \sqrt{2} }{ \sqrt{2} }

\rm \:  =  \: \dfrac{(1.732 - 1) \sqrt{2} }{2}

\rm \:  =  \: \dfrac{0.732 \times \sqrt{2} }{2}

\rm \:  =  \: 0.366 \sqrt{2}

Hence,

\rm :\longmapsto\: \boxed{ \rm{ \: \:  \:   \sqrt{\dfrac{ \sqrt{3}  - 1}{ \sqrt{3}  + 1} } = 0.366 \sqrt{2} \:  \:  \: }}

▬▬▬▬▬▬▬▬▬▬▬▬▬▬▬▬▬▬▬▬▬▬▬▬

<h2>More Identities to know :- </h2>

(a + b)² = a² + 2ab + b²

(a - b)² = a² - 2ab + b²

a² - b² = (a + b)(a - b)

(a + b)² = (a - b)² + 4ab

(a - b)² = (a + b)² - 4ab

(a + b)² + (a - b)² = 2(a² + b²)

(a + b)³ = a³ + b³ + 3ab(a + b)

(a - b)³ = a³ - b³ - 3ab(a - b)

3 0
3 years ago
True or false? in a two-column proof, the left column states your reasiong
wel

Answer:

true

Step-by-step explanation:

7 0
3 years ago
Read 2 more answers
Rectangles F and H are similar. If rectangle F has dimensions of 5x10 and rectangle H has dimensions of 15 by an unknown amount.
enyata [817]

Answer:

The answer is 30 or 7.5

Step-by-step explanation:

There are two answers because you haven't specified whether the 15 corresponds with the 5 or the 10 so I did both.

If the 15 corresponds with the 5 then the scale factor is 3 because 15 ÷ 5 = 3. To find the unknown amount you have to multiply the 10 by 3 to get 30.

If the 15 corresponds with the 10 then the scale factor is 1.5 because 15 ÷ 10 = 1.5. To find the unknown amount you have to multiply the 5 by 1.5 to get 7.5.

So depending on whether the 15 corresponds to the dimension 5 or 10 you have two answer, you can use the one that applies to you.

8 0
4 years ago
The function y = f(x) is graphed below. What is the average rate of change of the
Serjik [45]

The average rate of change of the function in the given interval -3 ≤ x ≤-1 is 10.

<h3>What is the average rate of change?</h3>

The average Rate of Change of the function f(x) can be calculated as;

f(x) = \dfrac{f(b) - f(a)}{b-a}

Interval -3 ≤ x ≤-1

a = -3, b = -1

f(a) = f(-3) = -20

f(b) = f(-1) = 0

Step 2: Find Average

f(x) = \dfrac{f(b) - f(a)}{b-a}\\\\\\f(x) = \dfrac{f(-1) - f(-3)}{-1-(-3)}\\\\\\f(x) = \dfrac{0 - (-20)}{2}\\\\f(x) = 10

Therefore, the average rate of change of the function in the given interval -3 ≤ x ≤-1 is 10.

Learn more about average rate;

brainly.com/question/20784578

#SPJ1                  

3 0
2 years ago
A bag of Halloween M&amp;M’s contains 4 orange, 5 brown and 6 yellow candies. Two candies are selected without replacement. Let
Montano1993 [528]
P(A)= 4+5+6= 15/2= 75%
P(B)= 6+4=10  5/10= 50%
P(C)= 5+4=9    6/9= 66.6%

4 0
3 years ago
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