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azamat
2 years ago
11

Calculate the range for the set of numbers 23, 17, 43, 50, 29, 23, 43

Mathematics
2 answers:
FrozenT [24]2 years ago
7 0
33 It is the maximum number minus the minimum answer to get that
Veseljchak [2.6K]2 years ago
3 0

Answer:

The answer is 33

Step-by-step explanation: Range is maximum number in the set minus the minimum number in the set of numbers.

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What time would it be 3 hours after 6:05
SpyIntel [72]
3+6=9

The time would be 9:05
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3 years ago
500 in the ratio 2:3
irina1246 [14]
500 in 2:3 is saying that there are five different parts (2 + 3)
This means that 500 needs to be split into five, which is 100.
After that all you need to do is put 2 'sections' on one side and 3 on the other.

For example, 2 : 3 = 2( x 100) : 3( x 100)
                                = 200 : 300
8 0
3 years ago
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What is the slope of the line with points A and B?
marshall27 [118]

Answer:

-1

Step-by-step explanation:

A = (0,0)

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3 0
3 years ago
C represents the commission on her sales.
vlabodo [156]
First simplify the expression.
1/3(1,650+0.15c)
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3 0
3 years ago
At a local University, it is reported that 81% of students own a wireless device. If 5 students are selected at random, what is
Sphinxa [80]

Answer:

34.87% probability that all 5 have a wireless device

Step-by-step explanation:

For each student, there are only two possible outcomes. Either they own a wireless device, or they do not. The probability of a student owning a wireless device is independent from other students. So we use the binomial probability distribution to solve this question.

Binomial probability distribution

The binomial probability is the probability of exactly x successes on n repeated trials, and X can only have two outcomes.

P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}

In which C_{n,x} is the number of different combinations of x objects from a set of n elements, given by the following formula.

C_{n,x} = \frac{n!}{x!(n-x)!}

And p is the probability of X happening.

81% of students own a wireless device.

This means that p = 0.81

If 5 students are selected at random, what is the probability that all 5 have a wireless device?

This is P(X = 5) when n = 5. So

P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}

P(X = 5) = C_{5,5}.(0.81)^{5}.(0.19)^{0} = 0.3487

34.87% probability that all 5 have a wireless device

5 0
3 years ago
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