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Alekssandra [29.7K]
3 years ago
6

At a hockey game a vendor sold a combine total of 248 sodas and hot dogs. The number of sodas sold was three times the number of

hot dogs sold. Find the number of sodas and the number of hot dogs sold
Mathematics
1 answer:
8_murik_8 [283]3 years ago
5 0

Answer:

total =248

sodas=3x

hot dogs=x

3x+x=248

4x =248

x=62

hot dogs =62

sodas=3×62

sodas=186

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Dafna11 [192]

Answer:

Option B is correct.

Step-by-step explanation:

The distance formula used is:

d=\sqrt{(x_{2}-x_{1})^2+(y_{2}-y_{1})^2+(z_{2}-z_{1})^2}

We need to find distance between origin and other point (3,-4,5)

Origin is: (0,0,0)

x₁ = 0, y₁ = 0, z₁ =0 and x₂= 3, y₂= -4 and z₂ = 5

Putting values in the distance formula we get:

d=\sqrt{(3-0)^2+(-4+0)^2+(5-0)^2}\\d=\sqrt{(3)^2+(-4)^2+(5)^2}\\d=\sqrt{9+16+25}\\d=\sqrt{50}\\d=7

The Distance from the origin to the point (3, −4, 5) is 7 units.

Option B is correct.

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3 years ago
Two triangles are similar. The dimensions of the first are 7, 8, and 10, while the dimensions of the second one are 3.5, 4, and
Irina-Kira [14]
The scale factor used is .5 because 7, 8, and 10 multiplied by .5 will equal 3.5, 4, and 5.
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Read 2 more answers
The volume of a cubical box is
creativ13 [48]

The sides length of the cubical box is 3.8 cm if the volume of a cubical box is 54.872 cm³ option second is correct.

<h3>What is a cube?</h3>

It is defined as three-dimensional geometry that has six square faces and eight vertices.

We have a volume of a cubical box is 54.872 cm³

V = 54.872 cm³

As we know the volume of the cube:

V = side³

54.872 = side³

Taking cube root on both sides:

side = 3.8 cm

Thus, the sides length of the cubical box is 3.8 cm if the volume of a cubical box is 54.872 cm³ option second is correct.

Learn more about the cube here:

brainly.com/question/15420947

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8 0
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20 POINTS
RUDIKE [14]

<em>The correct expressions are as follows:</em>

7^{\frac{1}{5}} \cdot 49^{\frac{7}{5}} Equivalent 343

7^{\frac{1}{5}} \cdot 49^{\frac{7}{5}} Not Equivalent 49

7^{\frac{1}{5}} \cdot 49^{\frac{7}{5}} Equivalent 7^{\frac{1}{5}} \cdot 7^{\frac{14}{5}}

7^{\frac{1}{5}} \cdot 49^{\frac{7}{5}} Not Equivalent 49^{\frac{2}{10}} \cdot 7^{\frac{1}{5}}

\texttt{ }

<h3>Further explanation</h3>

Let's recall following formula about Exponents and Surds:

\boxed { \sqrt { x } = x ^ { \frac{1}{2} } }

\boxed { (a ^ b) ^ c = a ^ { b . c } }

\boxed {a ^ b \div a ^ c = a ^ { b - c } }

\boxed {\log a + \log b = \log (a \times b) }

\boxed {\log a - \log b = \log (a \div b) }

<em>Let us tackle the problem!</em>

\texttt{ }

7^{\frac{1}{5}} \cdot 49^{\frac{7}{5}} = 7^{\frac{1}{5}} \cdot (7^2)^{\frac{7}{5}}

7^{\frac{1}{5}} \cdot 49^{\frac{7}{5}} = 7^{\frac{1}{5}} \cdot (7)^{2\times \frac{7}{5}}

7^{\frac{1}{5}} \cdot 49^{\frac{7}{5}} = \boxed{7^{\frac{1}{5}} \cdot 7^{\frac{14}{5}}}

7^{\frac{1}{5}} \cdot 49^{\frac{7}{5}} = 7^{\frac{1}{5} + \frac{14}{5}}

7^{\frac{1}{5}} \cdot 49^{\frac{7}{5}} = 7^{\frac{15}{5}}

7^{\frac{1}{5}} \cdot 49^{\frac{7}{5}} = 7^{3}

7^{\frac{1}{5}} \cdot 49^{\frac{7}{5}} = \boxed{343}

\texttt{ }

<em>From the results above, it can be concluded that the correct statements are:</em>

7^{\frac{1}{5}} \cdot 49^{\frac{7}{5}} Equivalent 343

7^{\frac{1}{5}} \cdot 49^{\frac{7}{5}} Not Equivalent 49

7^{\frac{1}{5}} \cdot 49^{\frac{7}{5}} Equivalent 7^{\frac{1}{5}} \cdot 7^{\frac{14}{5}}

7^{\frac{1}{5}} \cdot 49^{\frac{7}{5}} Not Equivalent 49^{\frac{2}{10}} \cdot 7^{\frac{1}{5}}

\texttt{ }

<h3>Learn more</h3>
  • Coefficient of A Square Root : brainly.com/question/11337634
  • The Order of Operations : brainly.com/question/10821615
  • Write 100,000 Using Exponents : brainly.com/question/2032116

<h3>Answer details</h3>

Grade: High School

Subject: Mathematics

Chapter: Exponents and Surds

Keywords: Power , Multiplication , Division , Exponent , Surd , Negative , Postive , Value , Equivalent , Perfect , Square , Factor.

4 0
3 years ago
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Please Help I Will Thank You And Give You 5 Stars
enyata [817]

Answer:

The first blank is m, the rest aren’t very clear

Step-by-step explanation:

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