For this case we have the following functions:

We must find
. By definition we have to:

So:

Finally, the composite function is:

Answer:

The Answer is -
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Answer:
Yes, △ABC ∼ △FED by AA postulate.
Step-by-step explanation:
Given:
Two triangles ABC and FED.
m∠A = m∠B
m∠C = m∠A + 30°
m∠E = m∠F = 
m∠D =
°.
Now, let m∠A = m∠B = 
So, m∠C = m∠A + 30° = 
Now, sum of all interior angles of a triangle is 180°. Therefore,
m∠A + m∠B + m∠C = 180

Therefore, m∠A = 50°, m∠B = 50° and m∠C = m∠A + 30° = 50 + 30 = 80°.
Now, consider triangle FED,
m∠D+ m∠E + m∠F = 180

Therefore, m∠F = 50°
m∠E = 50° and
m∠D = 
So, both the triangles have congruent corresponding angle measures.
m∠A = m∠F = 50°
m∠B = m∠E = 50°
m∠C = m∠D = 80°
Therefore, the two triangles are similar by AA postulate.
Answer:
y = x + 4
Step-by-step explanation:
Since x > 5, x-3 > 0, x + 2 > 0 and x - 5 > 0
So Ix - 3I = x - 3, Ix + 2I = x + 2 and x - 5 = x - 5
Therefore, y = x - 3 + x + 2 - x + 5
y = x + 4
That is 2(1/7 + 1/2)
= 2( 2/14 + 7/14)
= 2 * 9/14
= 18/14 = 9/7 units ( or 1 2/7 units)