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damaskus [11]
3 years ago
7

Please help me please!! −

Mathematics
1 answer:
jek_recluse [69]3 years ago
6 0

Answer:

Step-by-step explanation:

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Answer:

4th box

Step-by-step explanation:

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2 years ago
Which expression shows the area of the base of each pyramid? (One-fourth x) squared in.2 (One-third x) squared in.2 (One-half x)
777dan777 [17]

Answer:

(a) Area = (\frac{x}{4})^2

Step-by-step explanation:

The question is incomplete. (See comment for complete question).

From the completed question, we have:

Total\ base\ length = x

n = 8 --- number of pyramids

Required

An expression for the area of the base

The total base length of the pyramid represents the perimeter of the base.

And since the base is a square, then the following relationship exist.

Total\ base\ length = 4L

Where L represents the length of each side.

This gives

4L = x

Make L the subject

L = \frac{x}{4}

The area of the base is then calculated as:

Area = L^2

Area = (\frac{x}{4})^2

5 0
3 years ago
Read 2 more answers
Any help please if you can ig?
erastova [34]

Answer:

56756

Step-by-step explanation:

4 0
3 years ago
!!!KHAN ACADEMY!!! help please
barxatty [35]
Use photomath lollllll
3 0
2 years ago
---- PLEASE HELP <3 .. with steps :( <3
Zielflug [23.3K]

1) 6, 18, 54

2) 5/3, 14/9, 41/27

3) 1.5, 2.5, 2.5

Step-by-step explanation:

1)

The function that we have in this problem is

g(x)=3x

We want to find the first 3 iterations.

The initial value is:

x = 2

To find the value of the 1st iteration, we just substitute this value into the expression of the function, and we get:

g_1(x)=3x=3\cdot 2 = 6

The to find the value of the 2nd iteration, we just substitute this value into the expression of the function, and we get:

g_2(x)=3\cdot g_1(x)=3\cdot 6 = 18

Finally, the 3rd iteraction is given by:

g_3(x)=3g_2(x)=3\cdot 18=54

2)

Here in this problem the function that we have to use is

g(x)=\frac{1}{3}x+1

The initial value is

x=2

So the first iteration is given by

g_1(x)=\frac{1}{3}\cdot 2 + 1 = \frac{5}{3}

To find the 2nd iteration, we substitute this value into g(x) again:

g_2(x)=\frac{1}{3}g_1+1=\frac{1}{3}\cdot \frac{5}{3}+1=\frac{5}{9}+1=\frac{14}{9}

Finally, to find the 3rd iteration, we substitute this value into g(x) again:

g_3(x)=\frac{1}{3}\cdot \frac{14}{9}+1=\frac{14}{27}+1=\frac{41}{27}

3)

The function in this problem is

g(x)=-|x-2|+3

The initial value is

x = 0.5

So, the first iteration is:

g_1(x)=-1|0.5-2|+3=-1|-1.5|+3=-1\cdot 1.5 +3=-1.5+3=1.5

The second iteration is given by

g_2(x)=-|g_1-2|+3=-|1.5-2|+3=--0.5+3=2.5

Finally, the 3rd iteration is

g_3(x)=-|g_2-2|+3=-|2.5-2|+3=-0.5+3=2.5

5 0
3 years ago
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