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3 years ago

Math study page book show work !!!

Mathematics

1 answer:

GREYUIT [131]3 years ago

3 0

Step-by-step explanation:

for that we use Pythagoras, as the distance is always the baseline (Hypotenuse) of a right-angled triangle created by the x and y coordinate differences between the 2 points.

15.

distance² = (8-3)² + (9-2)² = 5² + 7² = 25 + 49 = 74

distance = sqrt(74) = 8.602325267...

16.

we need to write down the point coordinates first :

(-4, 3)

(1, -3)

distance² = (1 - -4)² + (-3 - 3)² = 5² + (-6)² = 25 + 36 = 61

distance = sqrt(61) = 7.810249676...

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PLEASE HURRY!!!!

Pavel [41]

Answer:

Step-by-step explanation:

You are going to roll two dice.

If you roll one die, then there are 6 possible outcomes: $1, 2, 3, 4, 5, 6$

If you roll two dice, then there are $6\times 6=36$ possible outcomes:

$\begin{array}{cccccc}1-1&1-2&1-3&1-4&1-5&1-6\\ \\2-1&2-2&2-3&2-4&2-5&2-6\\ \\3-1&3-2&3-3&3-4&3-5&3-6\\ \\4-1&4-2&4-3&4-4&4-5&4-6\\ \\5-1&5-2&5-3&5-4&5-5&5-6\\ \\6-1&6-2&6-3&6-4&6-5&6-6\end{array}$

Here the first number is the number rolled on the first die, the second number is the number rolled on the second die.

5 0

4 years ago

Read 2 more answers

Define the variable plz ASAP!!!!

Ksivusya [100]

There are 20 questions on the quiz.

4 0

3 years ago

P(x)= 3x^3-5x^2-14x-4

nexus9112 [7]

$\displaystyle\\
P(x)=3x^3-5x^2-14x-4\\\\
D_{-4}=\{-4;~-2;~\underline{\bf -1};~1;~2;~4\}\\\\
\text{We observe that } \frac{-1}{3} \text{ is a solution of the equation:}\\
3x^3-5x^2-14x-4=0\\\\
$

$\displaystyle\\
\text{Verification}\\\\
3x^3-5x^2-14x-4=\\\\
=3\times\Big(-\frac{1}{3}\Big)^3-5\times\Big(-\frac{1}{3}\Big)^2-14\times\Big(-\frac{1}{3}\Big)-4=\\\\
=-\frac{1}{9}-\frac{5}{9}+\frac{14}{3}-4=\\\\
=-\frac{6}{9}+\frac{14}{3}-4=\\\\
=-\frac{6}{9}+\frac{42}{9}- \frac{4\times 9}{9}=\\\\
 =-\frac{6}{9}+\frac{42}{9}- \frac{36}{9}= \frac{42-6-36}{9}=\frac{42-42}{9}=\frac{0}{9}=0\\\\
\Longrightarrow~~~P(x)~\vdots~\Big(x+ \frac{1}{3}\Big)\\\\
\Longrightarrow~~~P(x)~\vdots~(3x+1)$

$\displaystyle\\
3x^3-5x^2-14x-4=0\\
~~~~~-5x^2 = x^2 - 6x^2\\
~~~~~-14x =-2x-12x \\
3x^3+x^2 - 6x^2-2x-12x-4=0\\
x^2(3x+1)-2x(3x+1) -4(3x+1)=0\\
(3x+1)(x^2-2x -4)=0\\\\
\text{Solve: } x^2-2x -4=0\\\\
x_{12}= \frac{-b\pm \sqrt{b^2-4ac}}{2a}=\\\\=\frac{2\pm \sqrt{4+16}}{2}=\frac{2\pm \sqrt{20}}{2}=\frac{2\pm 2\sqrt{5}}{2}=1\pm\sqrt{5}\\\\
x_1 =1+\sqrt{5}\\
x_2 =1-\sqrt{5}\\
\Longrightarrow P(x)= 3x^3-5x^2-14x-4 =\boxed{(3x+1)(x-1-\sqrt{5})(x-1+\sqrt{5})}$

7 0

3 years ago

The wholesale price for a desk is $199. A certain furniture store marks up the wholesale price by 24%. Find the price of the des

eduard

Answer:

246.76$

Step-by-step explanation:

199 x .24 =

47.76

199 + 47.76 =

246.76

5 0

3 years ago

Find the common difference of the arithmetic sequence 13, 16, 19,...13,16,19,...

VLD [36.1K]

Answer:

the common difference is plus 3

4 0

3 years ago