A basketball team has 10 players. Before each game, the coach picks 2 of those players to carry the team's
1 answer:
The different group of 2 players that the coach can pick is 45 groups.
<h3>Selection of groups</h3>
The selection of groups of 2 player can be done using the method of combination.
<h3>Different groups of 2 players</h3>The different group of 2 players that the coach can pick from the 10 players is calculated as follows;
n = 10C2
Thus, the different group of 2 players that the coach can pick is 45 groups.
Learn more about combinations here: brainly.com/question/25821700
You might be interested in
Answer:
Step-by-step explanation:
<u>Function modeling</u>
Real-life situations often require the help of mathematics to model numerically what happens when the variables involved can change. It could even be used to predict some expected outcomes from those models.
The problem states Janice receives $.40 per pound when he recycles less or equal than 99 pounds of aluminum. If x is the number of recycled pounds, then the amount of money he receives is
We also know that if he recycles more than 100 pounds of aluminum, the pay increases to $0.5 per pound. In that case, the amount of money is
This is a case where the function is defined differently depending on the conditions of the input variable x. It's called a piecewise function. The function can be written as
Note the function is not well constructed because there is a gap for x=100 where M is not defined. If we establish that for 100 pounds the payment is $0.5, then the second piece would include x=100
1. Check the picture attached.
let P, M, N be the points :P(5, -2), M(5, 0), N(0, -2)
ABP is the angle with measure ∅, where BA is the initial ray and BP the terminal ray.
2. m(PNM)=∅ as can be easily checked
In triangle PNM, NP=5, PM=2 and NM=
units
3. let opp=opposite side, adj=adjecent side, hyp=hypothenuse
sin ∅ = opp/hyp=
cos ∅ = adj/hyp=
tan ∅ = opp/adj=2/5
cot ∅ = adj/opp=5/2
sec ∅ = hyp/adj=
csc ∅ = hyp/opp=
let P, M, N be the points :P(5, -2), M(5, 0), N(0, -2)
ABP is the angle with measure ∅, where BA is the initial ray and BP the terminal ray.
2. m(PNM)=∅ as can be easily checked
In triangle PNM, NP=5, PM=2 and NM=
3. let opp=opposite side, adj=adjecent side, hyp=hypothenuse
sin ∅ = opp/hyp=
cos ∅ = adj/hyp=
tan ∅ = opp/adj=2/5
cot ∅ = adj/opp=5/2
sec ∅ = hyp/adj=
csc ∅ = hyp/opp=