Adding the two equations
3x + 6y + 3x - 6y = 36+0
6x = 36
x = 6
.
subtracting second equation from first
(3x + 6y ) - (3x-6y) =36 -0
12y = 36
y = 3
.
therefore
x = 6 and y = 3
(6,3)
<span>
Let's analyze Hannah's work, step-by-step, to see if she made any mistakes. </span>In Step 1, Hannah wrote

<span> as the sum of two separate derivatives </span>

<span>using the </span><span>sum rule.
</span>
This step is perfectly fine. In Step 2,

was kept as it is, and

was rewritten as

using the constant rule.Indeed, according to the constant rule, the derivative of a constant number is equal to zero.
This step is perfectly fine. In Step 3,

was rewritten as

supposedly using the constant multiple rule.
The problem is that according to the constant multiple rule,

should be rewritten as

and not as

.
<span>
Therefore, Hannah made a mistake in this step.</span>
B is the answer!
Explanation:
m^2 n^2 fits into both, you can take m^2 n^2 out of it both.
m is a common factor since you can take m out of both but it’s not the greatest common factor.
2n & 2m wouldn’t even be a common factor bc there is no 2n or 2m in neither.
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Below are the choices:
A) (2, 6)
<span>B) (4, 6) </span>
<span>C) (2, 5) </span>
<span>D) (4, 5)
</span>
The answer should be: (4, 5)
<span>E = (8, 8) -----> E' = (4, 4) = (8/2, 8/2)
</span><span>F = (8, 10) -----> F' = (8/2, 10/2) = (4, 5)</span>
Answer:
(-5/2,-4)
Step-by-step explanation: