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miss Akunina [59]

3 years ago

5

The total cost of 4 goldfish and 3 guppies is $29. 3 goldfish and 5 guppoes cost $30. How much does each cost

1 answer:

Aneli [31]3 years ago

5 0

let the goldfish be x and the guppies be y

4x + 3y = 29...equ(1)

3x + 5y = 30...equ(2)

multiplying equation 1 by 5 and equation 2 by 3

20x + 15y = 145...equ(1)

9x + 15y = 90...equ(2)

subtracting equation 2 from 1

11x = 55

∴x = 5

substituting the value of x into equation

4(5) + 3y = 29

20 + 3y = 29

3y = 9

∴y =3

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o-na [289]

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$\large\boxed{x=4\pm2\sqrt6}$

Step-by-step explanation:

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Dvinal [7]

It would be two trapezoids and a rectangle + two triangles

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iren [92.7K]

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The following six independent length measurements were made (in feet) for a line: 736.352, 736.363, 736.375, 736.324, 736.358, a

horrorfan [7]

Answer:

Assuming population data

$\sigma = \sqrt{0.000354}=0.0188$

Assuming sample data

$s = \sqrt{0.000425}=0.0206$

Step-by-step explanation:

For this case we have the following data given:

736.352, 736.363, 736.375, 736.324, 736.358, and 736.383.

The first step in order to calculate the standard deviation is calculate the mean.

Assuming population data

$\mu = \frac{\sum_{i=1}^6 X_i}{6}$

The value for the mean would be:

$\mu = \frac{736.352+736.363+736.375+736.324+736.358+736.383}{6}=736.359$

And the population variance would be given by:

$\sigma^2 = \frac{\sum_{i=1}^6 (x_i-\bar x)}{6}$

And we got $\sigma^2 =0.000354$

And the deviation would be just the square root of the variance:

$\sigma = \sqrt{0.000354}=0.0188$

Assuming sample data

$\bar X = \frac{\sum_{i=1}^6 X_i}{6}$

The value for the mean would be:

$\bar X = \frac{736.352+736.363+736.375+736.324+736.358+736.383}{6}=736.359$

And the population variance would be given by:

$s^2 = \frac{\sum_{i=1}^6 (x_i-\bar x)}{6-1}$

And we got $s^2 =0.000425$

And the deviation would be just the square root of the variance:

$s = \sqrt{0.000425}=0.0206$

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3 years ago

PLS ANSWER QUICK THANK YOU

Serjik [45]

Answer:

0.001

Step-by-step explanation:

i hope this helps :)

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