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snow_tiger [21]
3 years ago
8

Write an exponential function that passes through (0, 3) and (1, 6).

Mathematics
1 answer:
Ilya [14]3 years ago
3 0

Answer: y=x^8-x^7+x^6-x^5+x^4+x^3+x^2+3

Step-by-step explanation:

here is an example function that satisfies the requirement:

y=x^8-x^7+x^6-x^5+x^4+x^3+x^2+3

if you plug in x=0,

you get y= 3, which satisfies (0,3)

if you plug in x=1,

you get y = 1 - 1 + 1 - 1 + 1 + 1 + 1 + 3,

you get y=6, which satisfies (1,6)

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List the first three wholenumbers greater than 50 that will have a remainder of 7 when you divide by 9/ ?
daser333 [38]

Answer:

52, 61 and 70

Step-by-step explanation:

Given

Divisor = 9

Remainder = 7

Required

Determine first 3 possible dividends

The relationship between the dividend,\ divisor,\ quotient\ and\ remainder is:

Dividend = Divisor * Quotient + Remainder

Substitute: Divisor = 9 and Remainder = 7

Dividend = 9* Quotient + 7

Since the Dividends must be greater than 50, then the values of the quotient will be 5, 6 and 7

So, we have:

Dividend = 9* 5 + 7 = 45 + 7 = 52

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Dividend = 9* 7 + 7 = 63 + 7 = 70

<em>Hence, the three numbers are: 52, 61 and 70</em>

8 0
3 years ago
What’s the correct answer for this question?
evablogger [386]

Answer:

PQ = 6

Step-by-step explanation:

Using tangent-secant theorem,

(PQ)² = (PR)(PS)

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