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3 years ago

Four consecutive multiples of 10 have a sum of 300. What is the least of these numbers?

Mathematics

2 answers:

AnnyKZ [126]3 years ago

4 0

60 + 70 + 80 + 90 = 300

K. 60

Shkiper50 [21]3 years ago

3 0

20 + 30 + 40 + 50 = 140 -No

30 + 40 + 50 + 60 = 180 -No

40 + 50 + 60 + 70 = 220 -No

50 + 60 + 70 + 80 = 260 -No

60 + 70 + 80 + 90 = 300 -Yes

Your final answer:
<em>K. 60</em>

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Answer:

A) 0.1538

Step-by-step explanation:

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Initially, we have 15 students, of which 10 have none experience. So the probability that M1 is chosen as a student with no experience is $\frac{10}{15}$ .

Then, there are 14 students, of which 9 have no experience. So the probability that M2 is chosen as a student with no experience is $\frac{9}{14}$ .

For the third member, there are 13 students, of which 8 have no experience. So the probability that M3 is chosen as a student with no experience is $\frac{8}{13}$ .

For the last member, there are 12 students, of which 7 have no experience. So the probability that M4 is chosen as a student with no experience is $\frac{7}{12}$ .

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$P = \frac{10}{15}*\frac{9}{14}*\frac{8}{13}*\frac{7}{12} = 0.1538$

The correct answer is:

A) 0.1538

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3 years ago

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Step-by-step explanation:

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3 years ago

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