S casts a "shadow" on the x-y plane given by the set

Each cross section is a square whose side length is determined by the vertical distance between y = 1 and y = x², which is |1 - x²|. But since -1 ≤ x ≤ 1, this distance simplifies to 1 - x².
The volume of an infinitesimally thin section is then (1 - x²)² ∆x (where ∆x represents its thickness), and so the volume of S is

The integrand is even, so this integral is equal to twice the integral over [0, 1] :

Answer:
1. -1/2b
2. 3a/b^2
3. 3b^2/1a^2
4. -1a^2b/2
Step-by-step explanation:
Simplified answers and then the variables cancel out each out as much as they can (That's the best way to explain it)
Answer:
(d) 1/√(s³)
Step-by-step explanation:
The expression can be simplified by making use of the rules of exponents.
<h3>Rules of exponents</h3>
The relevant rules are ...
![a^b\cdot a^c=a^{b+c}\\\\(a^b)^c=a^{bc}\\\\\left(\dfrac{a}{b}\right)^c=\dfrac{a^c}{b^c}\\\\a^{b/c}=\sqrt[c]{a^b}](https://tex.z-dn.net/?f=a%5Eb%5Ccdot%20a%5Ec%3Da%5E%7Bb%2Bc%7D%5C%5C%5C%5C%28a%5Eb%29%5Ec%3Da%5E%7Bbc%7D%5C%5C%5C%5C%5Cleft%28%5Cdfrac%7Ba%7D%7Bb%7D%5Cright%29%5Ec%3D%5Cdfrac%7Ba%5Ec%7D%7Bb%5Ec%7D%5C%5C%5C%5Ca%5E%7Bb%2Fc%7D%3D%5Csqrt%5Bc%5D%7Ba%5Eb%7D)
<h3>Application</h3>
The given expression can be simplified by applying these rules.

Question 1. 5b + 2 = 17
Step 1. Subtract 2 from both sides of the equation.
5b+2-2=17-2
Step 2. Then simplify.
5b=15
Step 3. Finally divide by 5.
5b/5=15/5
Answer: b=3
Question 3.
Step 1. Subtract 9 from both sides.
9+4b-9=17-9
Step 2. And simplify.
4b=8
Step 3. Finally divide by 4.
4b/4=8/4
Answer: b=2
Hope this helps! :)