This is an exponential decay problem.
Using the equation Y = a *(1-rate)^time
where Y is the future value given as 12,000 and a is the starting value given as 13,000.
The rate is also given as 5%.
The equation becomes:
12,000 = 13,000(1-0.05)^x
12,000 = 13,000(0.95)^x
Divide each side by 13000:
12000/13000 = 0.95^x/13000
12/13 = 0.95^x
Use the natural log function:
x = ln(12/13) / ln(0.95)
x = 1.56 years. ( this will equal 12,000
Round to 2 years it will be less than 12000.
Answer:
(b) 2.175 miles to 2.185 miles
Step-by-step explanation:
When a value is rounded, the original "exact" value is presumed to be within 1/2 of the value of one least-significant unit of the rounded number.
<h3>Application</h3>
A rounded value of 2.18 has a least-significant digit with a place value of 0.01 units. Half that value is the "margin of error". That is, the range of numbers that would be rounded to 2.18 is ...
2.18-0.005 ≤ x < 2.18+0.005
2.175 ≤ x < 2.185 . . . . miles
U can either look at ur graph...and where the line crosses the x axis is ur x intercept...which is (-3,0)
OR
take ur equation and sub in 0 for y, and solve for x, ur x intercept.
2x - y = -6
2x - 0 = -6
2x = -6
x = -6/2
x = -3.....so ur x intercept is (-3,0)
Thee function is given as:
<span>v(t)=t^2−2tv(t)=t^2−2t
</span>(a) What is the initial velocity?
Base from the function, the initial velocity would be zero.
(b) When does the object have a velocity of zero?
It would be during time zero. Also, at a time equal to two.
Answer:
x = 12
Step-by-step explanation:
