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spayn [35]
2 years ago
11

Hey I need help with please show your work Thank you.

Mathematics
2 answers:
cupoosta [38]2 years ago
6 0
Not my work but I did give you the answer, have a nice day!

nata0808 [166]2 years ago
4 0

Answer:

315

Step-by-step explanation:

→ Substitute the first equation into the second

a + 21a = 330

→ Simplify

22a = 330

→ Solve for a

a = 15

→ Multiply answer by 21

15 × 21 = 315

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If your grocery bill came to $205.67 and was reduced to $145.90 after coupons, what is the percent decrease?
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Answer:

I believe the answer is -29.06%

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A diagram of a rectangular pool with the diagonal of 50 meters is shown below. Connected to the pool is a square shaped kid’s po
NeTakaya
The pool is 40 since half of the other rectangle is 50 which the 2 halfs equal 100 and we already know the top side measurement which is 40 and 2 sides of 40 equal 80 and there’s 20 left so this concludes that’s the sides are 10 and square sides are congruent to each other which concludes that’s the AREA is 40
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The Magazine Mass Marketing Company has received 10 entries in its latest sweepstakes. They know that the probability of receivi
Serjik [45]

Answer:

P(X>4)= 0.624

Step-by-step explanation:

Given that

n = 10

p= 0.5 ,q= 1 - p = 0.5

Two fifth of 10 = 2/5 x 10 =4

It means that we have to find probability P(X>4).

P(X>4)= 1 -P(X=0)-P(X=1)-P(X=2)-P(X=3)-P(X=4)

We know that

P(X=x)=(_{x}^{n})\ p^xq^{n-x}

P(X=0)=(_{0}^{10})\ 0.5^0\ 0.5^{10}=0.0009

P(X=1)=(_{1}^{10})\ 0.5^1\ 0.5^{9}=0.0097

P(X=2)=(_{2}^{10})\ 0.5^2\ 0.5^{8}=0.043

P(X=3)=(_{3}^{10})\ 0.5^3\ 0.5^{7}=0.117  

P(X=4)=(_{4}^{10})\ 0.5^3\ 0.5^{7}=0.205

P(X>4)= 1 -P(X=0)-P(X=1)-P(X=2)-P(X=3)-P(X=4)

P(X>4)= 1 -0.0009 - 0.0097 - 0.043 - 0.117-0.205

P(X>4)= 0.624

8 0
2 years ago
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Illinois license plates used to consist of either three letters followed by three digits or two letters followed by four digits.
DENIUS [597]

Answer:

The probability that a randomly chosen plate contains the number 2222 is 0.000028 approximately.

The probability that a randomly chosen plate contains the sub-string HI is 0.002548  approximately.

Step-by-step explanation:

Consider the provided information.

Illinois license plates used to consist of either three letters followed by three digits or two letters followed by four digits.

Part (A)

Let A is the ways in which plates consist of three letters followed by three digits and B is the ways in which two letters followed by four digits.

Here repetition is allow. The number of alphabets are 26 and the number of distinct digits are 10.

The numbers of ways in which three letters followed by three digits can be chosen is: 26\times 26\times 26 \times 10 \times 10 \times10

26^3\times 10^3=17576000

The numbers of ways in which two letters followed by four digits can be chosen is: 26\times 26\times 10 \times 10 \times 10 \times10

26^2\times 10^4=6760000

Hence, the total number of ways are 17576000 + 6760000 = 24336000

Randomly chosen plate contains the number 2222 that means the first two letter can be any alphabets but the rest of the digit should be 2222.

Thus, the total number of ways that a randomly chosen plate contains the number 2222 number are: 26^2=676

The probability that a randomly chosen plate contains the number 2222 is:

\frac{676}{24336000} \approx 0.000028

Part (B)

The number of ways in which chosen plate contains the sub-string HI:

If three letters followed by three digits plate contains the sub-string HI, then the number of possible ways are:

26\times 1\times10^3+1\times 26\times10^3

If two letters followed by four digits plate contains the sub-string HI, then the number of possible ways are:

1\times 10^4

Thus, the total number of ways that a randomly chosen plate contains the sub-string HI are:

1\times 10^4+26\times 1\times10^3+1\times 26\times10^3

62000

From part (A) we know that the total number of ways to chose a number plate is 24336000.

The probability that a randomly chosen plate contains the sub-string HI is:

\frac{62000}{24336000} \approx 0.002548

7 0
3 years ago
A painting measure 40 cm by 35 cm how many squared cm does its surface cover
miskamm [114]

Answer: Its surface covers  1400 cm²

Explanation:

Since the length of painting = 40 cm

Breadth of painting = 35 cm

Since we know that area of rectangle is product of dimensions.

∴ Area of painting = length × breadth

= 40 cm × 35 cm

= 1400 cm²

∴ Its surface cover  1400 cm².

8 0
2 years ago
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