All categories

2 years ago

A round cake has a diameter of 30 cm. What is the circumference of the cake?

Mathematics

2 answers:

andre [41]2 years ago

8 0

Answer: 56

Step-by-step explanation:

Just trust me I had this question on a quiz

Nonamiya [84]2 years ago

3 0

Answer:

The circumference of cake board is 35π cm

You might be interested in

HELP WILL MARK BRAINLIEST TO BEST ANSWER!!!!!!!!<br> I NEED ASAP

Bond [772]

Answer is B

Find perimeter then divide by 3 (because price is per 3 meters) then times by 500 to get the answer

4 0

3 years ago

4 gallons, 3 quarts are equal to how many pints

Lelu [443]

Answer:

14 pints

Step-by-step explanation:

1 gallon = 8 pints

3 quarts= 6 pints

8+6=14

3 0

3 years ago

It costs John $13.50 to take Mary out for the evening. Sixty percent of this total was for theater tickets. What was the cost of

masya89 [10]

4.05 dollars for one ticket.

8 0

3 years ago

HElp me there are two that have not been answered

Greeley [361]

Answer: the answer is 34

Step-by-step explanation:

8 0

3 years ago

Read 2 more answers

Use the Newton-Raphson method to find the root of the equation f(x) = In(3x) + 5x2, using an initial guess of x = 0.5 and a stop

xxMikexx [17]

Answer with explanation:

The equation which we have to solve by Newton-Raphson Method is,

f(x)=log (3 x) +5 x²

$f'(x)=\frac{1}{3x}+10 x$

Initial Guess =0.5

Formula to find Iteration by Newton-Raphson method

$x_{n+1}=x_{n}-\frac{f(x_{n})}{f'(x_{n})}\\\\x_{1}=x_{0}-\frac{f(x_{0})}{f'(x_{0})}\\\\ x_{1}=0.5-\frac{\log(1.5)+1.25}{\frac{1}{1.5}+10 \times 0.5}\\\\x_{1}=0.5- \frac{0.1760+1.25}{0.67+5}\\\\x_{1}=0.5-\frac{1.426}{5.67}\\\\x_{1}=0.5-0.25149\\\\x_{1}=0.248$

$x_{2}=0.248-\frac{\log(0.744)+0.30752}{\frac{1}{0.744}+10 \times 0.248}\\\\x_{2}=0.248- \frac{-0.128+0.30752}{1.35+2.48}\\\\x_{2}=0.248-\frac{0.17952}{3.83}\\\\x_{2}=0.248-0.0468\\\\x_{2}=0.2012$

$x_{3}=0.2012-\frac{\log(0.6036)+0.2024072}{\frac{1}{0.6036}+10 \times 0.2012}\\\\x_{3}=0.2012- \frac{-0.2192+0.2025}{1.6567+2.012}\\\\x_{3}=0.2012-\frac{-0.0167}{3.6687}\\\\x_{3}=0.2012+0.0045\\\\x_{3}=0.2057$

$x_{4}=0.2057-\frac{\log(0.6171)+0.21156}{\frac{1}{0.6171}+10 \times 0.2057}\\\\x_{4}=0.2057- \frac{-0.2096+0.21156}{1.6204+2.057}\\\\x_{4}=0.2057-\frac{0.0019}{3.6774}\\\\x_{4}=0.2057-0.0005\\\\x_{4}=0.2052$

So, root of the equation =0.205 (Approx)

Approximate relative error

$=\frac{\text{Actual value}}{\text{Given Value}}\\\\=\frac{0.205}{0.5}\\\\=0.41$

Approximate relative error in terms of Percentage

=0.41 × 100

= 41 %

7 0

3 years ago